bitbucket-25253 (7/26/2010)
webrunnerEasy enough to find out ...
CREATE TABLE #T(userid INT)INSERT INTO #T
SELECT 1 UNION ALL
SELECT 1 UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6 UNION ALL
SELECT 7
SELECT COUNT(DISTINCT userid) AS '(1)' FROM #T
SELECT DISTINCT COUNT(userid)AS '(2)' FROM #T
Results:
(1) (2)7 8
Thanks - that's a nice illustration of the difference.
- webrunner
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A SQL query walks into a bar and sees two tables. He walks up to them and asks, "Can I join you?"
Ref.: http://tkyte.blogspot.com/2009/02/sql-joke.html