Home Forums Testing Center Question of the Day (QOD) Question of the Day for 22 Dec 2006 RE: Question of the Day for 22 Dec 2006

  • December 13, 2007 at 8:25 am

    #759856

    Just as a note, you don't have to use ABS to get the positive value for a negative, use

    declare @i int

    select @i = -5

    select -@i