p.shabbir (10/25/2013)
Sean Lange (10/25/2013)
p.shabbir (10/25/2013)
Hi Scuby,Try this.
select REPLACE(SUBSTRING(Your_Column,1,CHARINDEX('@',Your_Column)),'@','') Name from Your_Table NOLOCK
Thanks
sibi.
Why NOLOCK???
Sean,
At my work i used to specify "NOLOCK" at the end of select statement.Hence, by habit i mentioned there.You can take out that.
I would suggest that is a habit you learn to break unless you fully understand all the nasty stuff that hint brings to the table.
http://sqlblogcasts.com/blogs/tonyrogerson/archive/2006/11/10/1280.aspx
http://blogs.msdn.com/b/davidlean/archive/2009/04/06/sql-server-nolock-hint-other-poor-ideas.aspx
http://www.jasonstrate.com/2012/06/the-side-effect-of-nolock/[/url]
And i checked your query.
Only this is statement is working.
REPLACE(SUBSTRING(SEmail_Addr,1,CHARINDEX('@',SEmail_Addr)),'@','').
For other two got this error.
Error : Invalid length parameter passed to the LEFT or SUBSTRING function.
That's odd. The code I posted works perfectly. Now if you have email values that don't have an @ it would not work where the find code you posted does. I merely posted a couple of alternative ways. In now way did I mean that your fine code was not sufficient. In fact, I had yours in my list of possibilities.
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