The correct exceution of the query depends on ansi_warnings

set ansi_warnings off

DECLARE @i TABLE( mychar VARCHAR(10));

INSERT @i VALUES ('Steve'), ('Stephan'), ('Stephanie')

, ('Sterling'), ('Steppenwolf')

SELECT mychar

FROM @i

WHERE mychar LIKE 'Ste[^p]%'

It returns two rows in ONE resultset.

The question asks how many results ...?

The resultset is only ONE.