• elee1969 (7/3/2013)


    Eugene Elutin (7/3/2013)


    like this:

    SELECT q.Course_Code, 6-res.[4a] as [4a],6-res.[4b] as [4b], 6-res.[4c] as [4c], 6-res.[5a] as ,res.[5b],res.[5c],res.[6a],res.[6b],res.[6c],res.[7a],res.[7b],res.[7c],res.[7d],res.[7e] as converted

    FROM

    The above willnot compile as has quite few errors. You should be more accurate.

    Basically, in order to convert existing returned values as you requested, these values hould be subtrected out of 6, as:

    6 - 5 = 1

    6 - 4 = 2

    6 - 3 = 3

    6 - 2 = 4

    6 - 1 = 5

    Now, if you use the expression when retunring columns, they will need to be given aliases, therefore:

    6-res.[4a] as [4a]

    ,6-res.[4b] as [4b]

    ,...

    etc.

    Thanks Eugene !! I appreciate your help !!

    Right now 6 - 0 returns 6. What if i want to keep it as 0?