And here's a really obvious (yeah right!) way of making Lynn's example work:
declare @DateVal datetime;
set dateformat mdy;
set @DateVal = '2013-02-14T00:00:00';
select @DateVal;
go
declare @DateVal datetime;
set dateformat dmy;
set @DateVal = '2013-02-14T00:00:00';
select @DateVal;
go
If you haven't even tried to resolve your issue, please don't expect the hard-working volunteers here to waste their time providing links to answers which you could easily have found yourself.