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get the last active data


get the last active data

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sindhupavani123
sindhupavani123
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I’m trying to get the last active data and insert that in the current row of the table. Create table latest_value ( year int, [name] varchar(50), last_active varchar(50) )

go

Insert into latest_value Select 2010, 'Avinash', 'active' Union All Select 2011, 'Avinash','active' Union All select 2010,'Rahul','active' Union All Select 2012, 'Avinash','inactive'

SELECT * FROM latest_value

year name last_active
2010 Avinash active
2011 Avinash active
2010 Rahul active
2012 Avinash inactive

Desired output
year name last_active Status
2010 Rahul active 2010
2012 Avinash inactive 2011

Thanks in advance for the help!


GilaMonster
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Row_number partition by name order by year and filter for that = 1 (you'll need a subquery or CTE)

Gail Shaw
Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability

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ChrisM@Work
ChrisM@Work
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sindhupavani123 - Thursday, January 25, 2018 7:09 AM

I’m trying to get the last active data and insert that in the current row of the table. Create table latest_value ( year int, [name] varchar(50), last_active varchar(50) )

go

Insert into latest_value Select 2010, 'Avinash', 'active' Union All Select 2011, 'Avinash','active' Union All select 2010,'Rahul','active' Union All Select 2012, 'Avinash','inactive'

SELECT * FROM latest_value

year name last_active
2010 Avinash active
2011 Avinash active
2010 Rahul active
2012 Avinash inactive

Desired output
year name last_active Status
2010 Rahul active 2010
2012 Avinash inactive 2011

Thanks in advance for the help!



Your description doesn't appear to match your expected results - can you clarify?

“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
Exploring Recursive CTEs by Example Dwain Camps
sindhupavani123
sindhupavani123
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Sorry
I’m trying to get the last active year for the individual user and insert that year as a new column (Status) for that particular user.

Create table latest_value(year int,[name] varchar(50),last_active varchar(50))
go
Insert into latest_valueSelect 2010, 'Avinash', 'active'
Union All
Select 2011, 'Avinash','active'
Union All
select 2010,'Rahul','active'
Union All
Select 2012, 'Avinash','inactive'

SELECT *FROM latest_value

year name last_active
2010 Avinash active
2011 Avinash active
2010 Rahul active
2012 Avinash inactive


Desired output

year name last_active Status
2010 Rahul active 2010
2012 Avinash inactive 2011



I hope this make some sense?

Thank you
John Mitchell-245523
John Mitchell-245523
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If I've seen correctly through your illogical naming convention and the fact that your column headings are in the wrong order in your desired results, this should work. But only if you've posted on the wrong forum and you're not actually using SQL Server 2008.

WITH LatestDates AS (
SELECT
year
, name
, last_active
, ROW_NUMBER() OVER (PARTITION BY name ORDER BY year DESC) AS YearNo
, ROW_NUMBER() OVER (PARTITION BY name ORDER BY last_active, year DESC) AS StatusNo
FROM latest_value
)
, LatestActive AS (
SELECT
year
, name
, last_active AS Status
, YearNo
, FIRST_VALUE(year) OVER (PARTITION BY name ORDER BY StatusNo ASC) AS last_active
FROM LatestDates
)
SELECT
year
, name
, Status
, last_active
FROM LatestActive
WHERE YearNo = 1;


John
ChrisM@Work
ChrisM@Work
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Or maybe this:

SELECT lv.*, la.*

FROM (

SELECT *, rn = ROW_NUMBER() OVER(PARTITION BY [name] ORDER BY [year] DESC)

FROM #latest_value

) lv

OUTER APPLY (

SELECT [Status] = MAX([year])

FROM #latest_value lvi

WHERE lvi.name = lv.name AND lvi.last_active = 'active'

) la

WHERE lv.rn = 1



“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
Exploring Recursive CTEs by Example Dwain Camps
sindhupavani123
sindhupavani123
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Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)Old Hand (369 reputation)

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Points: 369 Visits: 61
This worked! Thanks a lot for the help!
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