July 14, 2006 at 2:34 am
Do you have a while - end clause or a recursive?
July 16, 2006 at 9:37 pm
No zubeyir...the syntax do not have a recursive...
this is the syntax which i mean, maybe u will get the better picture:
create view tso_cust_profile
as
select a.memberid as accountid,
a.srvlast, dbo.general_counter('m', a.srvlast, getdate()) as mthsrvlast,
a.srvtotal, dbo.srv_freq_categorizer(a.srvtotal) as srvfreq,
a.amttotal, dbo.amount_trans_categorizer(a.amttotal) as amttotalcatg,
b.title, b.account, b.gender,
dbo.general_counter('y',b.birthdate,getdate()) as age, b.maritalstatus,
b.employtype, b.livingstatus, b.industrialtype, b.education, b.jobtitle,
b.approvaldate, b.bankrefid, b.cardtype, b.cardlevel, b.validfrom,
b.validto, b.creditlimit, b.annualincome, b.monthlyexp, b.hobby,
c.type1total,
d.type2total,
e.type3total,
f.type4total,
g.type5total,
h.type6total,
i.type7total,
j.type8total,
k.type9total,
l.type10total,
m.type11total,
n.type12total,
o.type13total,
p.type14total,
q.type15total,
r.type16total,
s.type17total,
t.type18total,
u.type19total,
v.type20total
from tso_cust_service_profile a
left outer join cust_sapcic b
on a.memberid = b.accountid
left outer join tso_cust_service_type1 c
on a.memberid = c.memberid
left outer join tso_cust_service_type2 d
on a.memberid = d.memberid
left outer join tso_cust_service_type3 e
on a.memberid = e.memberid
left outer join tso_cust_service_type4 f
on a.memberid = f.memberid
left outer join tso_cust_service_type5 g
on a.memberid = g.memberid
left outer join tso_cust_service_type6 h
on a.memberid = h.memberid
left outer join tso_cust_service_type7 i
on a.memberid = i.memberid
left outer join tso_cust_service_type8 j
on a.memberid = j.memberid
left outer join tso_cust_service_type9 k
on a.memberid = k.memberid
left outer join tso_cust_service_type10 l
on a.memberid = l.memberid
left outer join tso_cust_service_type11 m
on a.memberid = m.memberid
left outer join tso_cust_service_type12 n
on a.memberid = n.memberid
left outer join tso_cust_service_type13 o
on a.memberid = o.memberid
left outer join tso_cust_service_type14 p
on a.memberid = p.memberid
left outer join tso_cust_service_type15 q
on a.memberid = q.memberid
left outer join tso_cust_service_type16 r
on a.memberid = r.memberid
left outer join tso_cust_service_type17 s
on a.memberid = s.memberid
left outer join tso_cust_service_type18 t
on a.memberid = t.memberid
left outer join tso_cust_service_type19 u
on a.memberid = u.memberid
left outer join tso_cust_service_type20 v
on a.memberid = v.memberid
the source of the data are coming from 2 tables only...but I have to make until 22 views to bring up together all the info that i need...
one of the table is containing at least two million records....the other only three hundred records
Is there any solution to running query above??
July 16, 2006 at 9:37 pm
No zubeyir...the syntax do not have a recursive...
this is the syntax which i mean, maybe u will get the better picture:
create view tso_cust_profile
as
select a.memberid as accountid,
a.srvlast, dbo.general_counter('m', a.srvlast, getdate()) as mthsrvlast,
a.srvtotal, dbo.srv_freq_categorizer(a.srvtotal) as srvfreq,
a.amttotal, dbo.amount_trans_categorizer(a.amttotal) as amttotalcatg,
b.title, b.account, b.gender,
dbo.general_counter('y',b.birthdate,getdate()) as age, b.maritalstatus,
b.employtype, b.livingstatus, b.industrialtype, b.education, b.jobtitle,
b.approvaldate, b.bankrefid, b.cardtype, b.cardlevel, b.validfrom,
b.validto, b.creditlimit, b.annualincome, b.monthlyexp, b.hobby,
c.type1total,
d.type2total,
e.type3total,
f.type4total,
g.type5total,
h.type6total,
i.type7total,
j.type8total,
k.type9total,
l.type10total,
m.type11total,
n.type12total,
o.type13total,
p.type14total,
q.type15total,
r.type16total,
s.type17total,
t.type18total,
u.type19total,
v.type20total
from tso_cust_service_profile a
left outer join cust_sapcic b
on a.memberid = b.accountid
left outer join tso_cust_service_type1 c
on a.memberid = c.memberid
left outer join tso_cust_service_type2 d
on a.memberid = d.memberid
left outer join tso_cust_service_type3 e
on a.memberid = e.memberid
left outer join tso_cust_service_type4 f
on a.memberid = f.memberid
left outer join tso_cust_service_type5 g
on a.memberid = g.memberid
left outer join tso_cust_service_type6 h
on a.memberid = h.memberid
left outer join tso_cust_service_type7 i
on a.memberid = i.memberid
left outer join tso_cust_service_type8 j
on a.memberid = j.memberid
left outer join tso_cust_service_type9 k
on a.memberid = k.memberid
left outer join tso_cust_service_type10 l
on a.memberid = l.memberid
left outer join tso_cust_service_type11 m
on a.memberid = m.memberid
left outer join tso_cust_service_type12 n
on a.memberid = n.memberid
left outer join tso_cust_service_type13 o
on a.memberid = o.memberid
left outer join tso_cust_service_type14 p
on a.memberid = p.memberid
left outer join tso_cust_service_type15 q
on a.memberid = q.memberid
left outer join tso_cust_service_type16 r
on a.memberid = r.memberid
left outer join tso_cust_service_type17 s
on a.memberid = s.memberid
left outer join tso_cust_service_type18 t
on a.memberid = t.memberid
left outer join tso_cust_service_type19 u
on a.memberid = u.memberid
left outer join tso_cust_service_type20 v
on a.memberid = v.memberid
the source of the data are coming from 2 tables only...but I have to make until 22 views to bring up together all the info that i need...
one of the table is containing at least two million records....the other only three hundred records
Is there any solution to running query above??
July 16, 2006 at 9:37 pm
No zubeyir...the syntax do not have a recursive...
this is the syntax which i mean, maybe u will get the better picture:
create view tso_cust_profile
as
select a.memberid as accountid,
a.srvlast, dbo.general_counter('m', a.srvlast, getdate()) as mthsrvlast,
a.srvtotal, dbo.srv_freq_categorizer(a.srvtotal) as srvfreq,
a.amttotal, dbo.amount_trans_categorizer(a.amttotal) as amttotalcatg,
b.title, b.account, b.gender,
dbo.general_counter('y',b.birthdate,getdate()) as age, b.maritalstatus,
b.employtype, b.livingstatus, b.industrialtype, b.education, b.jobtitle,
b.approvaldate, b.bankrefid, b.cardtype, b.cardlevel, b.validfrom,
b.validto, b.creditlimit, b.annualincome, b.monthlyexp, b.hobby,
c.type1total,
d.type2total,
e.type3total,
f.type4total,
g.type5total,
h.type6total,
i.type7total,
j.type8total,
k.type9total,
l.type10total,
m.type11total,
n.type12total,
o.type13total,
p.type14total,
q.type15total,
r.type16total,
s.type17total,
t.type18total,
u.type19total,
v.type20total
from tso_cust_service_profile a
left outer join cust_sapcic b
on a.memberid = b.accountid
left outer join tso_cust_service_type1 c
on a.memberid = c.memberid
left outer join tso_cust_service_type2 d
on a.memberid = d.memberid
left outer join tso_cust_service_type3 e
on a.memberid = e.memberid
left outer join tso_cust_service_type4 f
on a.memberid = f.memberid
left outer join tso_cust_service_type5 g
on a.memberid = g.memberid
left outer join tso_cust_service_type6 h
on a.memberid = h.memberid
left outer join tso_cust_service_type7 i
on a.memberid = i.memberid
left outer join tso_cust_service_type8 j
on a.memberid = j.memberid
left outer join tso_cust_service_type9 k
on a.memberid = k.memberid
left outer join tso_cust_service_type10 l
on a.memberid = l.memberid
left outer join tso_cust_service_type11 m
on a.memberid = m.memberid
left outer join tso_cust_service_type12 n
on a.memberid = n.memberid
left outer join tso_cust_service_type13 o
on a.memberid = o.memberid
left outer join tso_cust_service_type14 p
on a.memberid = p.memberid
left outer join tso_cust_service_type15 q
on a.memberid = q.memberid
left outer join tso_cust_service_type16 r
on a.memberid = r.memberid
left outer join tso_cust_service_type17 s
on a.memberid = s.memberid
left outer join tso_cust_service_type18 t
on a.memberid = t.memberid
left outer join tso_cust_service_type19 u
on a.memberid = u.memberid
left outer join tso_cust_service_type20 v
on a.memberid = v.memberid
the source of the data are coming from 2 tables only...but I have to make until 22 views to bring up together all the info that i need...
one of the table is containing at least two million records....the other only three hundred records
Is there any solution to running query above??
July 17, 2006 at 10:52 am
It may help to look at the views and tables being used. As the SQL for these may be extensive, if you send me a private email (PM), I can tell you where to send me the scripts so I can look at them and try to help. I have a feeling that you may not need all the views you are using but can't tell for sure until I see them.
Thanks,
Lynn ![]()
July 19, 2006 at 9:14 pm
Hi Lynn,
sorry, I forgot to copy the syntax for the UDFs ![]()
by the way, I've tried your SQL code and it works fine ...it took less time to run than the original code...the difference is until 6 minutes to retrieve the result...
thanx again for the help...![]()
regards,
Ady
July 19, 2006 at 9:14 pm
Hi Lynn,
sorry, I forgot to copy the syntax for the UDFs ![]()
by the way, I've tried your SQL code and it works fine ...it took less time to run than the original code...the difference is until 6 minutes to retrieve the result...
thanx again for the help...![]()
regards,
Ady
July 19, 2006 at 9:14 pm
Hi Lynn,
sorry, I forgot to copy the syntax for the UDFs ![]()
by the way, I've tried your SQL code and it works fine ...it took less time to run than the original code...the difference is until 6 minutes to retrieve the result...
thanx again for the help...![]()
regards,
Ady
July 19, 2006 at 9:14 pm
Hi Lynn,
sorry, I forgot to copy the syntax for the UDFs ![]()
by the way, I've tried your SQL code and it works fine ...it took less time to run than the original code...the difference is until 6 minutes to retrieve the result...
thanx again for the help...![]()
regards,
Ady
July 20, 2006 at 9:07 am
If it is running 6 minutes, you may still want to do some more work. I would suggest looking at your current indexes and perhaps running SQL Profiler to see if there are some changes that can be made to improve the performance of the query.
I am glad to hear that I was able to help.
Lynn
![]()
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