amit_adarsh (6/14/2012)
I don't think the answer is correct for the question (mentioed in screen shot).Because if you write like this , it will createa key that is treated as Primary Key and index wise it is clustered index
Please read the question carefully:
Below you see a part of a CREATE TABLE statement.
-- More column and constraint definitions below
Need an answer? No, you need a question
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