Confused with "Order by" output

Question

Post reply

Confused with "Order by" output

Bhuvnesh

SSC Guru

Points: 59351
More actions
March 4, 2010 at 5:46 am

#139151

declare @temp table ( id int , phn int)
insert into @temp
select 1 , 16454 UNION SELECT
2 , 5485 UNION SELECT
3 , 16454 UNION SELECT
4 , 11542 UNION SELECT
5 , 16454 UNION SELECT
6 , 5485
SELECT * FROM @temp T1
ORDER BY (SELECT COUNT(*) FROM @temp T2 WHERE T1.Phn = T2.Phn) DESC, ID ASC
whats the output of SELECT COUNT(*) FROM @temp T2 WHERE T1.Phn = T2.Phn
-------Bhuvnesh----------
I work only to learn Sql Server...though my company pays me for getting their stuff done;-)

Viewing 4 posts - 1 through 4 (of 4 total)

You must be logged in to reply to this topic. Login to reply

ChrisM@Work SSC Guru Points: 186127 More actions · Answer 1

SELECT *, (SELECT COUNT(*) FROM @temp T2 WHERE T1.Phn = T2.Phn)

FROM @temp T1

ORDER BY (SELECT COUNT(*) FROM @temp T2 WHERE T1.Phn = T2.Phn) DESC, ID ASC

^{“Write the query the simplest way. If through testing it becomes clear that the performance is inadequate, consider alternative query forms.” - Gail Shaw}

For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden

Bhuvnesh SSC Guru Points: 59351 More actions · Answer 2

thanks

-------Bhuvnesh----------
I work only to learn Sql Server...though my company pays me for getting their stuff done;-)

Paul White SSC Guru Points: 150468 More actions · Answer 3

Without duplicating the expression:

DECLARE @temp

TABLE (

id INTEGER NOT NULL,

phn INTEGER NOT NULL

);

INSERT @temp

(id, phn)

SELECT 1 , 16454 UNION ALL

SELECT 2 , 05485 UNION ALL

SELECT 3 , 16454 UNION ALL

SELECT 4 , 11542 UNION ALL

SELECT 5 , 16454 UNION ALL

SELECT 6 , 05485;

SELECT id, phn, phn_count = COUNT(*) OVER (PARTITION BY phn)

FROM @temp T1

ORDER BY

phn_count DESC,

ID ASC;

Or, removing it from the SELECT altogether:

SELECT T1.id,

T1.phn

FROM @temp T1

CROSS

APPLY (

SELECT COUNT(*) OVER (PARTITION BY phn)

) DV (phn_count)

ORDER BY

DV.phn_count DESC,

T1.id ASC;

Paul White
All articles available on SQL.kiwi
@SQL_Kiwi