2025-10-03
463 reads
2025-10-03
463 reads
2025-09-26
378 reads
2023-07-31
511 reads
2023-07-19
416 reads
There are a number of ways to generate key values in SQL Server tables including the IDENTITY column property, the NEWID() function and more recently, SEQUENCES. The IDENTITY column property is the earliest of these methods. It was introduced very early in the history of SQL Server and it is arguably the simplest approach. Though old, IDENTITY is still maintained in modern versions of SQL Server and is still relevant for simple use cases.
2020-05-21
8,467 reads
2024-12-23 (first published: 2020-05-05)
767 reads
2020-03-06
703 reads
2020-02-27
724 reads
In this tip we look at how to change the SQL Server setting for a tables identity column to not for replication for existing tables.
2019-05-03
2019-02-26
1,140 reads
By Brian Kelley
I will be leading an in-person Certified Information Systems Auditor (CISA) exam prep class...
EightKB is back again for 2026! The biggest online SQL Server internals conference is...
By HeyMo0sh
Working in DevOps long enough teaches you two universal truths: That’s exactly why I...
Hi all, I just started using VS Code to work with DB projects. I...
Comments posted to this topic are about the item Fun with JSON II
Comments posted to this topic are about the item Changing Data Types
I have some data in a table:
CREATE TABLE #test_data
(
id INT PRIMARY KEY,
name VARCHAR(100),
birth_date DATE
);
-- Step 2: Insert rows
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
t2.*
FROM OPENJSON(
(
SELECT t.* FROM #test_data AS t FOR JSON PATH
)
) t1
CROSS APPLY OPENJSON(t1.value) t2; See possible answers