Haidong Ji

I was a developer, working with VB, SQL Server, Access and lots of other Microsoft stuff.

I am currently a SQL Server DBA in my company in the Chicago area.

I am MCSD and MCDBA certified. In my spare time, if I have any, I like to do Linux, C and other open source project.

I can be reached at Happy_Haidong@yahoo.com

SQLServerCentral Article

Code Generation: Using SQL to Generate SQL and Other Code

SQL Server is a great platform against which to develop, but it can also be used as a code generation tool with a little creativity. Haidong Ji brings us a few techniques that can be used to automatically build T-SQL code and bcp code for importing and exporting data.

You rated this post out of 5. Change rating

2005-02-14

17,976 reads

Blogs

Cost Visibility: Tracking and Analysing Your Cloud Spend

By

One of the biggest challenges I’ve faced in cloud operations is maintaining clear visibility...

Whiling away an afternoon, thinking

By

I come to Heathrow often. Today is likely somewhere close to 60 trips to...

Black Box vs. Gray Box vs. White Box Testing

By

If your organization is spending money, then meaningful results are a must. Pen testing...

Read the latest Blogs

Forums

Fun with JSON II

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Fun with JSON II

Changing Data Types

By Steve Jones - SSC Editor

Comments posted to this topic are about the item Changing Data Types

Answering Questions On Dropped Columns

By Cláudio Silva

Comments posted to this topic are about the item Answering Questions On Dropped Columns

Visit the forum

Question of the Day

Fun with JSON II

I have some data in a table:

CREATE TABLE #test_data
(
    id INT PRIMARY KEY,
    name VARCHAR(100),
    birth_date DATE
);

-- Step 2: Insert rows  
INSERT INTO #test_data
VALUES
(1, 'Olivia', '2025-01-05'),
(2, 'Emma', '2025-03-02'),
(3, 'Liam', '2025-11-15'),
(4, 'Noah', '2025-12-22');
If I run this query, how many rows are returned?
SELECT t1.[key] AS row,
       t2.*
FROM OPENJSON(
     (
         SELECT t.* FROM #test_data AS t FOR JSON PATH
     )
             ) t1
    CROSS APPLY OPENJSON(t1.value) t2;

See possible answers