comma seperated parameter

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comma seperated parameter

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Naveen Kumar-807681

Posted Thursday, February 19, 2009 7:32 AM

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hi everybody,

i have 3 tables

1. customer_master(customerid, customername)
2. language_master(languageid, languagename)
3. customer_language(customerid, languageid)

i will get a parameter like 'english, kannada, punjabi' to my stored procedure or query. how simple can I get all the customers who speak all the 3 languages.

Who is wise? He that learns from everyone. Who is powerful? He that governs his passions. Who is rich? He that is content. Who is that? Nobody.:)

Post #660299

Grant Fritchey

Posted Thursday, February 19, 2009 9:21 AM

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There are a bunch of functions available in the Scripts area of the site. You do a search to track them down. Here's the one at the top of the list:http://www.sqlservercentral.com/scripts/Miscellaneous/31913/

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Post #660495

Naveen Kumar-807681

Posted Thursday, February 19, 2009 9:42 AM

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Thanks for ur reply. is there any other better way to do this?

Who is wise? He that learns from everyone. Who is powerful? He that governs his passions. Who is rich? He that is content. Who is that? Nobody.:)

Post #660535

Grant Fritchey

Posted Thursday, February 19, 2009 10:36 AM

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I know of four ways to do this, a function, a tally table, ad hoc queries or changing the data to XML. You have a function. This article is by Jeff Moden. He's the man where this is concerned. You can simply build a query so that you can insert your comma-delimited list into an IN clause, but that's going to cause recompiles and possibly bad performance. Converting to XML will work, but it's much more memory intensive and slower. I'd stick with the tally table (1st choice) or the function (2nd choice).

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"The credit belongs to the man who is actually in the arena, whose face is marred by dust and sweat and blood..." Theodore Roosevelt
The Scary DBA
Author of: SQL Server 2012 Query Performance Tuning
SQL Server 2008 Query Performance Tuning Distilled
and
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Product Evangelist for Red Gate Software

Post #660582

Jeff Moden

Posted Friday, February 20, 2009 9:51 PM

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Thanks for the kudo, Grant. :)

--Jeff Moden

"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".

First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column."

For better, quicker answers on T-SQL questions, click on the following...
http://www.sqlservercentral.com/articles/Best+Practices/61537/

For better answers on performance questions, click on the following...
http://www.sqlservercentral.com/articles/SQLServerCentral/66909/

Post #661961

Grant Fritchey

Posted Saturday, February 21, 2009 4:36 AM

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Credit where it's due.

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SQL Server 2008 Query Performance Tuning Distilled
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Post #662013

Ninja's_RGR'us

Posted Saturday, February 21, 2009 5:30 AM

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Credit is due and all good, but that still does not answer the question....

SELECT m.customerid, m.customername
FROM dbo.customer_master m
inner join dbo.customer_language cl on m.customerid = cl.customerid
inner join dbo.language_master lm on cl.languageid = lm.languageid
where lm.languagename IN (Select languageName from dbo.JeffsFunction(@Languages)) -- Fetch the languages here with Jeff's code

--this is the not so obvious part that answer the question you are asking
GROUP BY m.customerid, m.customername
HAVING COUNT(*) = (SELECT COUNT(*) FROM dbo.JeffsFunction)

You need to know how many languages are in the parameter string (can be in a separate parameter to avoid calling the split function twice), then you need to count how many languages are matching per customer and make sure that those 2 numbers are equal... hence that customer speaks all required languages.

Post #662016

Jeff Moden

Posted Saturday, February 21, 2009 8:18 AM

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Ninja's_RGR'us (2/21/2009)

Credit is due and all good, but that still does not answer the question....

True enough... we were waiting on some test data so we could show some tested code.

Naveen, take a look at the article in my signature below to get better answers quicker.

--Jeff Moden

Post #662042

Naveen Kumar-807681

Posted Saturday, February 21, 2009 9:08 AM

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Hi

Thanks for all the replies and suggestions. here is the query to get the required reuslt

SELECT c.customer
FROM #customer_master c
INNER JOIN
(
SELECT cl.customerid,COUNT(DISTINCT l.languagename) AS langcnt
FROM #customer_language cl
INNER JOIN #language_master l
ON l.languageid=cl.languageid
INNER JOIN (SELECT ltrim(f.Val) as val FROM dbo.split(@param,',')f)t
ON t.Val=l.languagename
GROUP BY cl.customerid
)tmp
ON tmp.customerid=c.customerid
WHERE langcnt=(SELECT COUNT(DISTINCT f1.Val) FROM dbo.split(@param,',')f1)

parametere will be like
@param = 'hindi, telugu'

Who is wise? He that learns from everyone. Who is powerful? He that governs his passions. Who is rich? He that is content. Who is that? Nobody.:)

Post #662048

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