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Home » Article Discussions » Article Discussions by Author » Discuss content posted by marcelo miorelli » how to find duplicated rows in a table
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marcelo miorelli
Posted Wednesday, June 11, 2008 8:35 AM
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Comments posted to this topic are about the item how to find duplicated rows in a table
Post #515223
adnan.korkmaz
Posted Wednesday, June 18, 2008 12:29 AM
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edit: this should be one of the most basic queries ever. so, i have been surprised why you have choosen to add an identity column and querying the table twice with joins, etc.

shouldn't the script below suit your needs?

select y,x
from t1 (NOLOCK)
group by y, x
having count(1) > 1
Post #518771
iskarta
Posted Wednesday, June 18, 2008 1:41 AM
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Infact, I didin't understand why you wrote like that code.
Where is the difference from below code.

I think It's very easy.

SELECT * FROM t1 WHERE y IN (
SELECT y FROM t1
GROUP BY y
HAVING COUNT(y)>1
)

Thanks.
Post #518800
ABHILASH DHONGDI
Posted Wednesday, June 18, 2008 2:07 AM
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this has gotta be the most pathetic script i've ever seen...

I'm surprised SSC even published this!!
Post #518810
Maysarah
Posted Wednesday, June 18, 2008 2:51 AM
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WHY???

you can use the following
SELECT
x,
y,
COUNT(y) AS How_Many_Times
FROM t1
GROUP BY x, y
HAVING (COUNT(y) > 1)

I don't understand 1.why do you have to add a rowid!! 2.what is the purpose of adding a third column (z) with a default value of zero!!!
Post #518825
Sam-263310
Posted Wednesday, June 18, 2008 6:09 AM
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ABHILASH DHONGDI (6/18/2008)
this has gotta be the most pathetic script i've ever seen...

I'm surprised SSC even published this!!


My thoughts, exactly. You can pick any line in the article and find problems with it. Awful.
Post #518918
Yorgs Neil
Posted Wednesday, June 18, 2008 8:41 AM
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I would have to agree with the other posts...
this script stinks on ice.

How does this warrant a hyperlink to the "solution script".

Lets keep the quality of the site high....
Fortunately, it usually is
Post #519122
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