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Forum Newbie
      
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How do I take a number like maybe 10.73 and remove the decimal place and making it a number like 1073. In other words I have to remove the decimal.
I need to do it using T-SQL
Thanks for any help
Ted
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SSC Rookie
      
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declare @mynum decimal(10,2)
declare @mynum1 int
set @mynum = 10.73
select @mynum1 = @mynum * 100
print @mynum
print @mynum1
or
declare @mynum decimal(10,2)
set @mynum = 10.73
select cast(@mynum * 100 as int)
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Forum Newbie
      
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Thanks for your prompt answer.
I was looking for something that would get rid of the decimal point
if the number was 10.73 or 10.733 or 10.7333 or 10.7
The decimal place being in any position
Thanks
Ted
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SSC Rookie
      
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what is the datatype of the field containing the decimal point?
If it's varchar you could:
declare @mynum varchar(20)
set @mynum = '10.7333'
select replace(@mynum,'.','')
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Forum Newbie
      
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The field is numeric(5,4)
but you have something there.
would it be possible to move it to a char field and then apply the logic you gave me
Again, thank you so much for your generous help
Ted
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declare @i decimal(10,2)
Set @i = 1078.734
select (left(@i, Charindex('.', @i, 1) - 1 ))
****************** Dinakar Nethi Life is short. Enjoy it. ******************
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SSC-Dedicated
           
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Doesn't matter if it's varchar or not... your method still works...
declare @i decimal(10,2)
Set @i = 1078.734
PRINT REPLACE(@i,'.','')
--Jeff Moden "RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".
First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column."
For better, quicker answers on T-SQL questions, click on the following... http://www.sqlservercentral.com/articles/Best+Practices/61537/
For better answers on performance questions, click on the following... http://www.sqlservercentral.com/articles/SQLServerCentral/66909/
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Forum Newbie
      
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Thank you all for your quick responses
I finally made it work with your help
Ted
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The problem with using the Replace string function is that 10.341 ends up as 1034100 if the numeric is defined with five places. If you want 10.342 to end up as 10341, 10.73 as 1073, 10.733 as 10733, 10.7333 as 107333 and 10.7 as 107, then the best way is to use numeric processes rather than string.
The only thing is, you have to define your working number to have enough places to the left to contain the entire value. So your example of storing 10.341 into a variable defined as decimal(5,4) is bogus--it only has one place to the left of the decimal point. So if your value is defined as "decimal(x,y)" then you have to declare a working variable as "decimal(x+y,y)" to contain the entire finished value.
declare @Original decimal( 10, 5 ),
@Working decimal( 15, 5 ), -- 10 + 5 = 15
@Result decimal( 15, 0 ); -- Doesn't need scale, only precision
Set @Original = 1078.734; -- This would be, say, an input parameter
-- First, make a copy into the working variable capable of handling it.
Set @Working = @Original;
-- Now set up the loop
Set @Result = Floor( @Working );
While @Result < @Working
begin
Set @Working = @Working * 10;
Set @Result = floor( @Working );
end--while
select @Result as Result, @Working as Working; The loop executes one time through for each significant digit to the right of the decimal point -- in this example, three times. The result is 1078734 instead of 107873400.
As an aside, does anyone know how to get the old "<pre></pre>" formatting back? This code IFCode shortcut sucks. Sure, the code goes into a nice text field :) but everything is double spaced.
Tomm Carr -- Version Normal Form -- http://groups.google.com/group/vrdbms
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