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Home » SQL Server 2008 » SQL Server 2008 - General » Rows being dropped in query
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montecarlo2079
Posted Thursday, February 21, 2013 1:23 PM
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Hi,

I am trying to count distinct days for medical claims using the icn, from date of service and to date of service.

Im using the sql below to create a temp table/calendar.

When the select statement runs, it omits about 39 icns in my list. is there something in the join that could be counting these records out?


CREATE TABLE #Calendar2(Dt DATETIME NOT NULL PRIMARY KEY);
;WITH cte AS
(
SELECT CAST('20120101' AS DATETIME) AS c
UNION ALL
SELECT DATEADD(dd,1,c) FROM cte
WHERE c < '20131231'
)
INSERT INTO #Calendar2 SELECT c FROM cte OPTION (MAXRECURSION 0);


SELECT
ICN,
COUNT(DISTINCT Dt) AS Days
FROM
AllOPBYDOS s
INNER JOIN #Calendar2 c ON
s.[from Date of service] >= c.Dt AND s.[to Date of service] < c.Dt+1
Where [Detail Status Code] = 'p'
GROUP BY
ICN;
Post #1422774
Eugene Elutin
Posted Friday, February 22, 2013 5:28 AM
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We have no idea what data you have in your tables, so only the guess:
You join on dates, so it may be that some dates in your expected data are such that they are not covered by the join.

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Post #1422998
montecarlo2079
Posted Friday, February 22, 2013 6:39 AM
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The table has 4 columns

ICN, From Date of service, To date of service, and detail status code
123,1/1/12 ,1/5/12 ,P
123,1/6/12 ,1/6/12 ,p
123,1/1/12 ,1/10/12 ,p


For each ICn I need to count only the distinct days per icn. in this example above, the answer would be 10. I dont want to count each day, but want the count of distinct days per ICN.

does that help?
Post #1423022
ScottPletcher
Posted Friday, February 22, 2013 11:33 AM
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is there something in the join that could be counting these records out?


Maybe in some cases "s.[to Date of service]" is NULL to indicate "no end date"?

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Post #1423187
Jeff Moden
Posted Friday, February 22, 2013 1:54 PM


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montecarlo2079 (2/22/2013)
The table has 4 columns

ICN, From Date of service, To date of service, and detail status code
123,1/1/12 ,1/5/12 ,P
123,1/6/12 ,1/6/12 ,p
123,1/1/12 ,1/10/12 ,p


For each ICn I need to count only the distinct days per icn. in this example above, the answer would be 10. I dont want to count each day, but want the count of distinct days per ICN.

does that help?


Not really. We don't know what the datatyes are, etc.

--Jeff Moden
"RBAR is pronounced "ree-bar" and is a "Modenism" for "Row-By-Agonizing-Row".

First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column."

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Post #1423253
lnardozi 61862
Posted Friday, February 22, 2013 7:09 PM
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select icn, DateDiff(dd,min(fromdt),isNull(max(todt),GETDATE())) daycnt from icns
group by icn
Post #1423309
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