Lidou123 (11/27/2012)

---

Hello,

I have a script problem.
I calculate data per week (group by week)
However, for indicators, I have business rules which apply in the month.
Here is the problem because I have weeks that are mounted on 2 different months.
I 'd like so:
1 - Identify the weeks that straddle two months
2 - For the week, identify the last day of the month is the day of the week.
3 - If the date is before Wednesday when the week belongs to month
Otherwise, the week belongs to the next month.

I hope I have clearly expressed my need.

And sorry for my English.:))

Lidou123 (11/28/2012)

---

Hi Jeff,

Thank you for your answer.
For my company, the first day of the week is Monday.
And the weeks are numbered by the start of the year.
We use the ISO Calendar.

All I want is to determine when a week is between two months, how many days are in the month M and how many are in the Month M+1.

I found the sql script in a Oracle forum but I don't know to translate it into T-SQL.

This is the URL where i found the Oracle Script. It s a french forum :)) : http://www.developpez.net/forums/d908298/bases-donnees/oracle/sql/nb-jours-semaine-cheval-2-mois/

And this the Oracle script:

WITH cal AS
(
SELECT date '2010-01-01' + level -1 AS dt
FROM dual
connect BY level <= 365
)
, sr AS
(
SELECT to_char(dt, 'yyyy-mm') AS mois ,
to_char(dt, 'iyyy"W"iw') AS iweek,
count(*) AS nb_jours,
count(*) over(partition BY to_char(dt, 'iyyy"W"iw')) AS nb_mois
FROM cal
GROUP BY to_char(dt, 'yyyy-mm'),
to_char(dt, 'iyyy"W"iw')
)
SELECT *
FROM sr
WHERE nb_mois = 2
ORDER BY mois ASC, iweek ASC;

MOIS IWEEK NB_DAY NB_MONTH
------- ------- ---------- ----------
2010-03 2010W13 3 2
2010-04 2010W13 4 2
2010-04 2010W17 5 2
2010-05 2010W17 2 2
2010-05 2010W22 1 2
2010-06 2010W22 6 2
2010-06 2010W26 3 2
2010-07 2010W26 4 2
2010-07 2010W30 6 2
2010-08 2010W30 1 2
2010-08 2010W35 2 2
2010-09 2010W35 5 2
2010-09 2010W39 4 2
2010-10 2010W39 3 2
2010-11 2010W48 2 2
2010-12 2010W48 5 2


I am waiting your answer.