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HELP ME !
12 posts, Page 2 of 2
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HELP ME !
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LutzM
LutzM
Posted Saturday, April 02, 2011 7:06 AM
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Group: General Forum Members
Last Login: Wednesday, April 24, 2013 3:17 PM
Points: 6,731,
Visits: 12,131
One possible answer is rather simple: 24.
Since the OP wants to do a calculation, we need to extract the numbers. For each question we have 4 times the number one and the questions are numbered 1, 2, and 3.
Therefore we get 1*(1+1+1+1) + 2*(1+1+1+1) + 3*(1+1+1+1) = 4 + 8 + 12 = 24.
Lutz
A pessimist is an optimist with experience.
How to get fast answers to your question
How to post performance related questions
Links for
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and
Dynamic Cross Tabs
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Post #1087806
SQLRNNR
SQLRNNR
Posted Saturday, April 02, 2011 8:30 AM
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Group: General Forum Members
Last Login: Today @ 8:43 AM
Points: 18,733,
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LutzM (4/2/2011)
One possible answer is rather simple: 24.
Since the OP wants to do a calculation, we need to extract the numbers. For each question we have 4 times the number one and the questions are numbered 1, 2, and 3.
Therefore we get 1*(1+1+1+1) + 2*(1+1+1+1) + 3*(1+1+1+1) = 4 + 8 + 12 = 24.
Wasn't the answer supposed to be 42 since everything can be answered by 42?
Jason
AKA CirqueDeSQLeil
I have given a name to my pain...
MCM SQL Server 2008
SQL RNNR
Posting Performance Based Questions - Gail Shaw
Posting Data Etiquette - Jeff Moden
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VLFs and the Tran Log - Kimberly Tripp
Post #1087808
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