

Hall of Fame
Group: General Forum Members
Last Login: Thursday, September 25, 2014 1:32 PM
Points: 3,021,
Visits: 461





SSChasing Mays
Group: General Forum Members
Last Login: Friday, January 11, 2013 12:41 PM
Points: 621,
Visits: 297





Hall of Fame
Group: General Forum Members
Last Login: Friday, May 9, 2014 12:47 AM
Points: 3,448,
Visits: 4,407


Explanation When precision is not specified with the decimal type, TSQL will use whatever precision would use the minimum space to store with the number it is converting to. This is not correct. SQL Server does not use "whatever precision" in this case. Here is the quote from BOL about precision (http://msdn.microsoft.com/enus/library/ms187746.aspx):
decimal and numeric (TransactSQL)
p (precision) The maximum total number of decimal digits that can be stored, both to the left and to the right of the decimal point. The precision must be a value from 1 through the maximum precision of 38. The default precision is 18. So when precision is not specified, SQL Server uses the value = 18.
Another quote from BOL:
s (scale) The maximum number of decimal digits that can be stored to the right of the decimal point. ... The default scale is 0; therefore, 0 <= s <= p.
Thus the expression "CONVERT(DECIMAL, @var)" is equal to "CONVERT(DECIMAL(18,0), @var)".
The batch from the example is equal to:
DECLARE @TestDecimal DECIMAL(8, 2) SET @TestDecimal = 275953.00 SELECT CONVERT( DECIMAL(18,0), @TestDecimal * 0.40 ) , CONVERT( DECIMAL(18,0), @TestDecimal ) * 0.40
Bhavesh_Patel Why answer differs when we are using the same function on same variable? In the first expression, the result of multiplication is converted to DECIMAL: CONVERT(DECIMAL, @TestDecimal * 0.40) = CONVERT(DECIMAL(18,0), 275953.00 * 0.40) = CONVERT (DECIMAL(18,0), 110381.2000) = 110381
In the second expression, the multiplier is converted to DECIMAL: CONVERT(DECIMAL, @TestDecimal) * 0.40 = CONVERT(DECIMAL(18,0), @TestDecimal) * 0.40 = 275953 * 0.40 = 110381.20




UDP Broadcaster
Group: General Forum Members
Last Login: Yesterday @ 5:26 PM
Points: 1,448,
Visits: 1,861


Bhavesh_Patel (12/15/2009) Why answer differs when we are using the same function on same variable? Because we're not actually running the function on the same variable. In the first column, we're doing the following:
CONVERT(DECIMAL, @TestDecimal * 0.40) Procedurally, this is 1. Multiply @TestDecimal by 0.40 2. Convert the result to DECIMAL, using the defaults (precision 18, scale 0). This is where the rounding occurs.
In column 2, we're doing CONVERT(DECIMAL, @TestDecimal) * 0.40 Procedurally, this is 1. Convert the value in @TestDecimal to DECIMAL, using the defaults (precision 18, scale 0). Since there's nothing to the right of the decimal, the value is not changed (although the data type is.) 2. Multiply this by 0.40. This creates a resulting value with digits to the right of the decimal point. See http://technet.microsoft.com/enus/library/ms190476.aspx for details on how SQL Server determines the precision and scale of a result of a mathematical operation on DECIMAL values.




SSCommitted
Group: General Forum Members
Last Login: Today @ 5:06 AM
Points: 1,900,
Visits: 6,971


Correct answer, but the explanation is completely wrong!




Hall of Fame
Group: General Forum Members
Last Login: Thursday, September 25, 2014 1:32 PM
Points: 3,021,
Visits: 461


I apologize for the incorrect explanation. I ran into a problem with this sort of thing about 3 months ago, and I looked all over BOL EXCEPT for the decimal data type page. Oops. I thought this was an undocumented problem, so I played with it for a couple hours and came to an incorrect conclusion. Hopefully Steve can fix it. Thank you to those who knew the correct reason behind this.




Ten Centuries
Group: General Forum Members
Last Login: Friday, January 9, 2015 6:09 PM
Points: 1,389,
Visits: 3,041


Julie, I've been through a similar experience posting a QOD and then finding out that I'd missed a point. Don't fret over that.
But, more important than a statement of the correct explanation for your results, folks should realize that NEITHER example is really a correct construction. You said it yourself in the explanation, so let's see the real effect of not specifying precision. This query:DECLARE @TestDecimal DECIMAL(8, 2) SET @TestDecimal = 275953.73 SELECT CONVERT( DECIMAL, @TestDecimal * 0.40 ) , CONVERT( DECIMAL, @TestDecimal ) * 0.40 , CONVERT( DECIMAL(8,2), @TestDecimal * 0.40 ) returns 110381 110381.60 110381.49 Only the last column, the one produced with an explicit precision, is correct. The CONVERT in the second column rounds the local variable 275953.73 to 275954 before doing the multiplication by 0.40.




SSCrazy
Group: General Forum Members
Last Login: Thursday, January 22, 2015 2:37 AM
Points: 2,624,
Visits: 587


The important point with this question is that you should never take anything for granted and always specify "optional" paramters/statements
/Håkan Winther MCITP:Database Developer 2008 MCTS: SQL Server 2008, Implementation and Maintenance MCSE: Data Platform




Old Hand
Group: General Forum Members
Last Login: Wednesday, July 20, 2011 10:32 AM
Points: 341,
Visits: 2,079


A better question would have been, what is the result of:
SELECT CONVERT(DECIMAL, 1.2)




SSCrazy Eights
Group: General Forum Members
Last Login: Today @ 6:34 AM
Points: 8,198,
Visits: 9,895


Julie Zeien (12/16/2009) I apologize for the incorrect explanation. I ran into a problem with this sort of thing about 3 months ago, and I looked all over BOL EXCEPT for the decimal data type page. Oops. I thought this was an undocumented problem, so I played with it for a couple hours and came to an incorrect conclusion. Hopefully Steve can fix it. Thank you to those who knew the correct reason behind this. Unfortunately it's very easy play with something for a while, form a mental model of what's going on, then try a few tests to check the model and when they work believe it is true. So don't worry to much at having done it  we all do it sometimes. The great trick is to find some tests that will check all the edge conditions implied by the model, which is sometimes very hard to do.
Tom



