Getting records created in a particular week

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Getting records created in a particular week

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Prakash-485822

Posted Monday, December 03, 2007 4:24 AM

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Dear All,
I want to get the records created in a particular week.
if i pass 3/12/2007 i want to get the records created in that week

Post #428641

Andras Belokosztolszki

Posted Monday, December 03, 2007 5:34 AM

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Prakash (12/3/2007)

Dear All,
I want to get the records created in a particular week.
if i pass 3/12/2007 i want to get the records created in that week

You could use :

datepart(wk, '3/12/2007')*53 + datepart(yyyy, '3/12/2007')

The first part gives you the week number in that year, the second part the year.
If the year is not needed (you have only data for the current year), then just use : datepart(wk, '3/12/2007')

Regards,
Andras

Andras Belokosztolszki, MCPD, PhD
GoldenGate Software

Post #428671

Ramesh Saive

Posted Monday, December 03, 2007 6:00 AM

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datepart(wk, '3/12/2007')*53 + datepart(yyyy, '3/12/2007')

The first part gives you the week number in that year, the second part the year.

Hey Andras, are u sure that will give what you said. Or you just missed something in between?

Here are the results from it...

SELECT	DATEPART( wk, '3/12/2007' ) * 53 + DATEPART( yyyy, '3/12/2007' ), 
		DATEPART( wk, '3/12/2007' ) * 53, DATEPART( wk, '3/12/2007' ), DATEPART( yyyy, '3/12/2007' )

--Results
2590		583		11		2007

Here is what I use in my projects...

DECLARE @sdtAnyDate SMALLDATETIME

SET @sdtAnyDate = '03-Dec-2007'

SELECT	DATEADD( DAY, 1 - DATEPART( dw, @sdtAnyDate), @sdtAnyDate ) AS WeekStartDate, 
		@sdtAnyDate AS InputDate,
		DATEADD( DAY, 7 - DATEPART( dw, @sdtAnyDate ), @sdtAnyDate ) AS WeekEndDate

--Ramesh

Post #428684

Andras Belokosztolszki

Posted Monday, December 03, 2007 6:06 AM

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You are right, (I probably need to sleep more) :)

A corrected version is:
DATEPART( wk, '3/12/2007' ) + (DATEPART( yyyy, '3/12/2007' )-1950) * 53

(the *53 should be on the year :), deducting 1950 will make the numbers even smaller)

Thanks,
Andras

Andras Belokosztolszki, MCPD, PhD
GoldenGate Software

Post #428689

Ramesh Saive

Posted Monday, December 03, 2007 6:14 AM

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Well, you need to interchange * with /

You are right, (I probably need to sleep more)

You'll surely need...:D

--Ramesh

Post #428692

Andras Belokosztolszki

Posted Monday, December 03, 2007 6:33 AM

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Ramesh (12/3/2007)

Well, you need to interchange * with /

You are right, (I probably need to sleep more)

You'll surely need...:D

Actually, I did indeed mean *.
multiplying the year (or part of it) by 53 will give a unique range of 53 numbers to every year. Adding the week number withing the year to this number (sine there are no more than 53 weeks a year) will assign a unique number to any year week pair. I really should have explained this :)

Regards,
Andras

Andras Belokosztolszki, MCPD, PhD
GoldenGate Software

Post #428701

Ramesh Saive

Posted Monday, December 03, 2007 6:48 AM

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I still couldn't understand what you're trying to point... Unsure

Multiplying the value gives me 3032, whereas I get 12 when divided...

I am curious to know, how the said value can be used in the context of the post?

--Ramesh

Post #428707

Andras Belokosztolszki

Posted Monday, December 03, 2007 7:26 AM

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Ramesh (12/3/2007)

I still couldn't understand what you're trying to point... Unsure

Multiplying the value gives me 3032, whereas I get 12 when divided...

I am curious to know, how the said value can be used in the context of the post?

Hi Ramesh,

if one would like to group items belonging to the same week, one can assign a unique number to all days of a particular week.

For example:

12/2/2007 3070 (Sunday, new week, new number)
12/3/2007 3070
12/4/2007 3070
12/5/2007 3070
12/6/2007 3070
12/7/2007 3070
12/8/2007 3070
12/9/2007 3071 (Sunday, new week, new number)
12/10/2007 3071
12/11/2007 3071
12/12/2007 3071
12/13/2007 3071
12/14/2007 3071
12/15/2007 3071
12/16/2007 3072 (Sunday, new week, new number)
12/17/2007 3072

So if I want all the items that are on the week 12/2/2007, then for the dates you are checking the formula should evaluate to 3070
(which you get by evaluating it for any day in the requested week, in this case '12/3/2007').

Generating a single number is just a convenience (or not). One can find a particular week by:

DATEPART( wk, somedayfromtable ) = DATEPART( wk, '3/12/2007' ) AND (DATEPART( yyyy, somedayfromtable ) = (DATEPART( yyyy, '3/12/2007' )

The above will get the items that belong to a particular week (the week for '3/12/2007'), the single number is equivalent
to the above statement (it just maps the year and week pair to a number).

Anyway, the above approach is useful if you would like to group by rows (which is the way I mis?understood the question Blush

). Sorry.

Your solution is also better for the original question from the point of view that it calculates the start and end date, and then it uses only datetime comparison, no need for calculations (or breaking up the datetime to a year and week number part)

Thanks for correcting me :)

Andras

Andras Belokosztolszki, MCPD, PhD
GoldenGate Software

Post #428725

Ramesh Saive

Posted Monday, December 03, 2007 7:40 AM

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Thanks Andras, for explaining what you meant earlier.:)

--Ramesh

Post #428736

Prakash-485822

Posted Monday, December 03, 2007 9:07 PM

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Dear All

I want the output in this way

Days No of.Requests
Mon 5
Tue 6
Wed 7
Thu 3
Fri 2
Sat 1

I will pass only the date to the query
Pls help me to solve this problem

Post #429092

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