September 30, 2003 at 10:41 am
I'm trying to set up a SQL Alert to run when a Failed login error is generated. For whatever reason, I can't seem to get this working. I have it set up to run on error 18456 (Failed login), I have the server set to log failed login attempts and I can see the entry in the log file, but the alert never occurs. Basically, I want a way to detect when someone is trying to hack into my database using a brute force approach. Any ideas?
October 1, 2003 at 12:10 am
did you stop/start sqlagent ? (is needed when you activate the first alert)
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October 1, 2003 at 1:46 am
Also you need to stop and restart sql server after changing the audit status.
The alert works fine for me (scripted below, excluding notifications).
IF (SELECT COUNT(*) FROM msdb.dbo.sysalerts WHERE name = N'Alert 18456 Login failed for user') < 1
BEGIN
EXECUTE msdb.dbo.sp_add_alert @name = N'Alert 18456 Login failed for user', @message_id = 18456, @severity = 0, @enabled = 1, @delay_between_responses = 60, @include_event_description_in = 5, @category_name = N'[Uncategorized]'
END
Steven
October 1, 2003 at 9:40 am
Along those same lines, are any of your alerts firing?
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October 1, 2003 at 12:20 pm
The script that steven sent worked. Thanks for all your help. I'm not sure what I was doing wrong, but it appears to be firing now.
June 22, 2015 at 12:16 pm
how can i modify this by saying that it would shoot an email only if somebody tries to login more then 3x .
Thanks
September 25, 2015 at 7:18 am
There's no logic in SQL Server for this. You'd need something to scan the SQL log and send you an alert. However, you'll need to define this. Do you mean 3 failed logins in a few minutes? In a day? Ever? The same user? Any user?
This isn't a simple thing. Is this SQL 2000?
September 25, 2015 at 7:29 am
Yes three failed logins in 5 min . Its sql server 2012
September 25, 2015 at 12:25 pm
Moving to the SQL 2012 forum. This was posted in SQL 2000.
In 2012, you might be able to do something with xEvents and a trigger when you get xx logins in xx time from a user. I'd think a Window function would help here. I don't have time to run a test, but this might help:
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