How to parse a string to equal length substrings in SQL

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How to parse a string to equal length substrings in SQL

sql_learner29

SSCrazy Eights

Points: 9107
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January 28, 2015 at 12:51 pm

#294279

Hi
I need help in a query...How to parse a string to equal length substrings in SQL
I am getting a long concatenated string from a query (CTVALUE1) and have to use the string in where clause by parsing every 6 characters..
CREATE TABLE [dbo].[PTEMP](
[ID] [char](10) NULL,
[name] [char](10) NULL,
[CTVALUE1] [char](80) NULL
)
INSERT INTO PTEMP
VALUES('11','ABC','0000010T00010L0001000T010C0001')
select * from ptemp
after parsing I have to use these values in a where clause like this
IN('000001','0T0001','0L0001','000T01','0C0001')
Now ,the values can change I mean the string may give 5 values(6 character) today and 10 tomorrow..
So the parsing should be dynamic.
Any help please
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Lowell SSC Guru Points: 323504 More actions · Answer 1

i have this old example, which might help:

/*--Results

id testout

---------- -------------------- --------------------------------------------------------------------------------

11 1 000001

11 2 0T0001

11 3 0L0001

11 4 000T01

11 5 0C0001

11 6

*/

CREATE TABLE [dbo].[PTEMP](

[ID] [char](10) NULL,

[name] [char](10) NULL,

[CTVALUE1] [char](80) NULL

)

INSERT INTO PTEMP

VALUES('11','ABC','0000010T00010L0001000T010C0001')

DECLARE @SplitLength int = 6

;with smallTally AS (

SELECT row_number() OVER (ORDER BY (SELECT NULL)) N FROM (VALUES (1), (1), (1), (1), (1), (1), (1), (1), (1), (1)) as T(N)

)

,testData AS (

SELECT * FROM (VALUES (1,'This is a long string to be split multiple times hopefully'), (2,'Cant touch me')) AS d(id,test)

)

SELECT id

,row_number() over (partition by id order by n)

,substring(CTVALUE1, ((N -1) * @SplitLength) + 1, @SplitLength) testout

FROM PTEMP d

CROSS APPLY (SELECT TOP ((len(CTVALUE1) / @SplitLength) + 1) N FROM smallTally) a

Lowell

--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

Luis Cazares SSC Guru Points: 183698 More actions · Answer 2

This is one possibility:

WITH E(n) AS(

SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL

SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1

)

,Tally(n) AS(

SELECT (ROW_NUMBER() OVER(ORDER BY (SELECT NULL)) * 6) - 5 FROM E a--, E b /*Uncomment for strings longer than 97 chars and up to 1536 chars long*/

)

select ID, name, SUBSTRING( CTVALUE1, n, 6), n

from ptemp, Tally

WHERE n < LEN( CTVALUE1);

It seems that Lowell was faster than me.

Luis C.
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