Need help in giving the expression for background color for a column

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Need help in giving the expression for background color for a column

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Mac1986

Posted Tuesday, January 08, 2013 4:25 AM

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Hi All,
I have a column 'RunTime' with following format of data in it. I need to give an expression for back ground color of this column as 'RED' if the RunTime >= 2 Hrs

For my earlier reports I was using = IIF(Fields!Runtime.Value > 2,"RED","SpringGreen") and it used to work. but I guess that because the column format was integer.

Can someone please help ASAP. Need to get this done tonight.

Thanks in Advance.

Post #1404137

anthony.green

Posted Tuesday, January 08, 2013 4:28 AM

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Could you not format out in the data set an int based column which is used in the expression, but not shown in the report?

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Post #1404140

Mac1986

Posted Tuesday, January 08, 2013 4:35 AM

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sorry for confusion. here is what the column looks like.

22 Hrs : 34 Mins
16 Hrs : 34 Mins
8 Hrs : 35 Mins
0 Hrs : 36 Mins

Now i need to put red color for the ones that are >= 2 Hrs

Post #1404145

Mac1986

Posted Tuesday, January 08, 2013 4:36 AM

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Is there a way that I can take only the first digit of the column and see if its >= 2 and mark it as red color in the expression?

Post #1404147

Mac1986

Posted Tuesday, January 08, 2013 4:37 AM

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That was just my thought. I mean please share your idea how mark the background color as red.

Post #1404148

anthony.green

Posted Tuesday, January 08, 2013 4:47 AM

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Could you not get left 1, convert it to int, then do > 2

CInt(Left(Fields!Field.Value,1)) > 2

Post #1404156

Mac1986

Posted Tuesday, January 08, 2013 5:11 AM

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How can I add a condition to the below expression? Please help

(CInt(Left(Fields!Runtime.Value,1)) >= 2,"Red"),"Transparent"

Post #1404168

anthony.green

Posted Tuesday, January 08, 2013 5:12 AM

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You would just build that into your background expression as you have done

=IIF( CInt( Left(Fields!Runtime.Value,1)) >= 2,"Red","Transparent")

Post #1404171

Mac1986

Posted Tuesday, January 08, 2013 5:19 AM

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That worked thanks a lot. You saved me big time tonight..

Post #1404175

anthony.green

Posted Tuesday, January 08, 2013 5:25 AM

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Doh moment

LEFT("16",1) = 1 which doesnt match the value as that should go red, do left 2, so change it to CInt(REPLACE(LEFT(Fields!Field.Value,2)," ","")), that way if it picks "1 " or "0 " it will remove the space and do the correct comparission

Post #1404177

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