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Forum Newbie
      
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If I run the following on SQL Server 2012 I get two different answers from the first two select statments.
Any reason why and what I need to do to avoid this. The second statement gives the wrong answer and that is the statement that I need to use in my code. With the change in statement 3 , I get the right answer but I am not getting the confidence that I should introduce the change in all my calculations.
select round((1400.05 / 4232.33 ) * 4180.06 ,2) --Statement 1
declare @v1 smallmoney = 1400.05, @v2 smallmoney = 4232.33, @v3 smallmoney = 4180.06
select round((@v1 / @v2 ) * @v3 ,2) --Statement 2
select round((@v1*1.0 / @v2 ) * @v3 ,2) --Statement 3
Thank you very much for the help.
Regards Divesh
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SSC Veteran
      
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I think the intermediate result from @v1 / @v2 is being truncated because you're using smallmoney data type.
Can you use a different datatype, or cast one value to decimal to make it clearer what's happening.
e.g.
select round((CAST(@v1 as decimal(18,2)) / @v2 ) * @v3 ,2) --Statement 2
or
declare @v1 smallmoney = 1400.05, @v2 smallmoney = 4232.33, @v3 smallmoney = 4180.06
select round((CAST(@v1 as decimal(18,2)) / @v2 ) * @v3 ,2), --Statement 2 CAST(@v1 as decimal(18,2)) / @v2, CAST(round((CAST(@v1 as decimal(18,2)) / @v2 ) * @v3 ,2) as SmallMoney) -- <----<<<
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Forum Newbie
      
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Laurie,
Thank you for your reply.
I guess if I force a cast to a decimal it will work since that is what happens when I add the "* 1.0" but I thought money or smallmoney was a decimal number.
Even if I change the datatype to money, I get the same results.
If we have to force a cast or conversion to a decimal type then does it mean that there is no point in using the money or smallmoney data type? !!! I hope this is not the conclusion of this. 
Thanks for any more leads on this.
Regards Divesh
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SSC Veteran
      
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Money & Smallmoney both have 4 decimal places, so that's why they lose the detail. If you're looking for accuracy it's better to use decimal.
It's all a bit of a minefield.
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UDP Broadcaster
      
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Discusses Issues with money. There are rounding issues with money and is probably not the best datatype to use in your scenario.
[url=http://www.sqlservercentral.com/Forums/Topic544518-9-1.aspx][/url]
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diveshps (9/27/2012)
Laurie, Thank you for your reply. I guess if I force a cast to a decimal it will work since that is what happens when I add the "* 1.0" but I thought money or smallmoney was a decimal number. Even if I change the datatype to money, I get the same results. If we have to force a cast or conversion to a decimal type then does it mean that there is no point in using the money or smallmoney data type? !!! I hope this is not the conclusion of this.  Thanks for any more leads on this. Regards Divesh
Speaking for myself, I always use DECIMAL to store dollar amounts to avoid exactly this sort of issue. I've never seen the point of money or smallmoney.
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Old Hand
      
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This behaviour is due to data type precedence.
(@v1 / @v2 ) * @v3 will return smallmoney ((@v1 * 1.0) / @v2 ) * @v3 will return numeric
This can be demonstrated like this:
DECLARE @v1 SMALLMONEY = 1400.05, @v2 SMALLMONEY = 4232.33;
SELECT @v1 / @v2 AS Val INTO TestTable1 SELECT @v1 / @v2 * 1.0 AS Val INTO TestTable2
EXEC sp_help TestTable1 EXEC sp_help TestTable2
DROP TABLE TestTable1 DROP TABLE TestTable2
And you will see the following:
TestTable1
Name - Val Type - smallmoney Length - 4 Precision - 10 Scale - 4
TestTable 2
Name - Val Type - numeric Length - 9 Precision - 13 Scale - 5
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SSCarpal Tunnel
       
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YOu may folow the money by tracing intermediate results:
select (1400.05 / 4232.33 ), (1400.05 / 4232.33 ) * 4180.06, round((1400.05 / 4232.33 ) * 4180.06 ,2) --Statement 1
declare @v1 smallmoney = 1400.05, @v2 smallmoney = 4232.33, @v3 smallmoney = 4180.06
select @v1, (@v1 / @v2 ), (@v1 / @v2 ) * @v3, round((@v1 / @v2 ) * @v3 ,2) --Statement 2
select @v1*1.0, (@v1*1.0 / @v2 ) ,(@v1*1.0 / @v2 ) * @v3 , round((@v1*1.0 / @v2 ) * @v3 ,2) --Statement 3
For most accurate calculations always use FLOAT data type (unless you need to handle more than 15 digigts, than use "big" decimals). Try use FLOAT in your example and you'll see that 4 digit returned by DECIMAL calculation is incorrect. Fortunateluy for you, it's beyond rounding precision.
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