• m.rajesh.uk (5/23/2016)


    Hi All,

    I need a query to get the data on hourly wise. Below query gives data on day basis.

    SELECT

    stat_date AS "date",

    DATEPART(YEAR,stat_date) AS year,

    SUBSTRING(CONVERT(VARCHAR(10),stat_date,102),0,8) AS year_month,

    DATEPART(MONTH,stat_date) AS month,

    DATEPART(WEEK,stat_date) AS week,

    MAX(nb_error) AS nb_error,

    MAX(nb_synchro) AS nb_synchro,

    MAX(avg_synchr_dur) AS avg_synchr_dur

    FROM

    (SELECT

    CAST(CONVERT(char(11), [time], 113) AS DATETIME) AS stat_date,

    COUNT(*) AS nb_error,

    0 AS nb_synchro,

    0 AS avg_synchr_dur

    FROM

    [UFC_Stats].[dbo].[repl_error] as re

    WHERE

    error_text LIKE 'The Merge Agent failed after detecting that retention-based%'

    and [time] >= DATEADD(day,-20, GETDATE())

    GROUP BY

    CAST(CONVERT(char(11), [time], 113) AS DATETIME)

    UNION ALL

    SELECT

    start_date AS synchro_date,

    0 AS nb_error,

    COUNT(session_id) AS nb_synchro,

    SUM(duration_sec) / COUNT(session_id) AS avg_synchr_dur

    FROM

    [UFC_Stats].[dbo].[repl_sess]

    WHERE

    publication LIKE 'UFC_Market-HH-Synchronization%'

    AND start_date >= DATEADD(day,-20, GETDATE())

    GROUP BY

    start_date

    UNION ALL

    SELECT

    CAST(CONVERT(char(11), t1.start_time, 113) AS DATETIME) AS synchro_date,

    0 AS nb_error,

    COUNT(session_id) AS nb_synchro,

    SUM(duration) / COUNT(session_id) AS avg_synchr_dur

    FROM

    distribution.dbo.MSmerge_sessions t1 INNER JOIN distribution.dbo.MSmerge_agents t2 on t1.agent_id = t2.id

    WHERE

    (publication LIKE 'UFC_Market-HH-Synch%') AND

    CAST(CONVERT(char(11), t1.start_time, 113) AS DATETIME) = CAST(CONVERT(char(11), GETDATE(), 113) AS DATETIME)

    GROUP BY

    CAST(CONVERT(char(11), t1.start_time, 113) AS DATETIME)) T1

    GROUP BY

    stat_date

    ORDER BY

    1 DESC

    We need DDL, sample data and expected results. For details on what to post, read the articles in my signature.

    (Rude question, rude answer)

    Luis C.
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