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Calculating age


Calculating age

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gilbert delarosa
gilbert delarosa
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This seems to work




DECLARE @DOB DATETIME

SET @DOB='9/19/2000'


SELECT FLOOR(DATEDIFF(DD,@DOB,GETDATE())/365.25)


Jeff Moden
Jeff Moden
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gilbert delarosa (9/20/2013)
This seems to work




DECLARE @DOB DATETIME

SET @DOB='9/19/2000'


SELECT FLOOR(DATEDIFF(DD,@DOB,GETDATE())/365.25)



Good try but it doesn't work...

DECLARE @DOB DATETIME

SET @DOB='01/01/2013'

SELECT FLOOR(DATEDIFF(DD,@DOB,'01/01/2014')/365.25)



Results:
---------------------------------------
0

(1 row(s) affected)


--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

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gilbert delarosa
gilbert delarosa
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But they wouldn't be 1 until after their BDay
or you could just

DECLARE @DOB DATETIME

SET @DOB='01/01/2013'

SELECT FLOOR((DATEDIFF(DD,@DOB,'01/01/2014')+1)/365.25)


Jeff Moden
Jeff Moden
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gilbert delarosa (9/20/2013)
But they wouldn't be 1 until after their BDay
or you could just

DECLARE @DOB DATETIME

SET @DOB='01/01/2013'

SELECT FLOOR((DATEDIFF(DD,@DOB,'01/01/2014')+1)/365.25)



Still doesn't work. Last I heard, you gained a year on your birthday and not the day before (Feb 29 babies sometimes excluded). :-)

DECLARE @DOB DATETIME

SET @DOB='01/01/2012'

SELECT FLOOR((DATEDIFF(DD,@DOB,'12/31/2012')+1)/365.25)




Results:

---------------------------------------
1

(1 row(s) affected)



--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
mister.magoo
mister.magoo
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Points: 10261 Visits: 7891

declare @dob datetime,@now date

set @dob='1 jan 2012'
set @now = '31 dec 2012'

select
datepart(year,@now) - datepart(year,@dob)
+
case
when dateadd(day
,datepart(day,@dob)-1
,dateadd(month
,datepart(month,@dob)-1
,dateadd(year
,datepart(year,@now)-1800
,'1 jan 1800'
)
)
) > @now
then -1
else 0
end



MM


select geometry::STGeomFromWKB(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  • ELSSON
    ELSSON
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    Is most simple:
    DECLARE @Birthday date = '1994/12/10'

    SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age
    Jeff Moden
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    ELSSON - Thursday, May 4, 2017 2:46 PM
    Is most simple:
    DECLARE @Birthday date = '1994/12/10'

    SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age


    I've not checked some of the possibilities nor have I checked it for performance but THAT IS mighty interesting especially for how it correctly determines ages when a Leap Day is involved.

    --Jeff Moden

    RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
    First step towards the paradigm shift of writing Set Based code:
    Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
    If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

    Helpful Links:
    How to post code problems
    How to post performance problems
    Forum FAQs
    ELSSON
    ELSSON
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    Group: General Forum Members
    Points: 12 Visits: 7
    Jeff Moden - Friday, May 5, 2017 5:53 AM
    ELSSON - Thursday, May 4, 2017 2:46 PM
    Is most simple:
    DECLARE @Birthday date = '1994/12/10'

    SELECT (CAST(CONVERT(VARCHAR(8), GETDATE(), 112) AS INT) - CAST(CONVERT(VARCHAR(8), @Birthday, 112) AS INT)) / 10000 AS Age


    I've not checked some of the possibilities nor have I checked it for performance but THAT IS mighty interesting especially for how it correctly determines ages when a Leap Day is involved.

    Thanks, this solution is ideal for BI, since the IDs of the dates are numbers of the same (Example "2017/05/05" has ID 20170505), so that the IDs would be used directly. This method is based on mathematics and bit-shift (in this case decimal shift)

    Go


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