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Calculating age


Calculating age

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yogaanand.me
yogaanand.me
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hi friends

i have Date of Birth column in my database , i dont have age column
i want to calculate accurate Age form DOB..
please help me..
Garadin
Garadin
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DECLARE @DOB datetime
SET @DOB = '1/20/1980'

SELECT CASE
WHEN DATEPART(DY,GETDATE()) >= DATEPART(DY,@DOB)
THEN DATEDIFF(YY,@DOB,GETDATE())
ELSE DATEDIFF(YY,@DOB,GETDATE())-1
END



Seth Phelabaum
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math martinez
math martinez
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Simple way to compute your age accurately.

A lot of query not exactly compute the age? yes! because sometime they only compute the datediff between DOB and datenow and divide it to 365.25 days and as a result they get a number with decimal something like 25 is the age with .06 decimal (age=25.06).

In this query you exactly get the age as is it.
Example 1
DOB = 11/15/1987 and
datenow =11/15/2012 the result would be
AGE=25

Example 2
DOB = 11/14/1987 and
datenow =11/15/2012 the result would be
AGE=24

SO HERE ARE THE QUERY

DECLARE @DOB SMALLDATETIME
SELECT @DOB = '11/15/1987'

SELECT
CASE
WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE())
ELSE DATEDIFF(YY,@DOB,GETDATE())-1

END AS AGE

HOPE I CAN HELP! :-)
Phil Parkin
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martinez.math (11/16/2012)
Simple way to compute your age accurately.

A lot of query not exactly compute the age? yes! because sometime they only compute the datediff between DOB and datenow and divide it to 365.25 days and as a result they get a number with decimal something like 25 is the age with .06 decimal (age=25.06).

In this query you exactly get the age as is it.
Example 1
DOB = 11/15/1987 and
datenow =11/15/2012 the result would be
AGE=25

Example 2
DOB = 11/14/1987 and
datenow =11/15/2012 the result would be
AGE=24

SO HERE ARE THE QUERY

DECLARE @DOB SMALLDATETIME
SELECT @DOB = '11/15/1987'

SELECT
CASE
WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE())
ELSE DATEDIFF(YY,@DOB,GETDATE())-1

END AS AGE

HOPE I CAN HELP! :-)


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Richard Warr
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Phil Parkin (11/16/2012)

You just responded to a three-year-old post!


So, just add 3 to the result and all will be well ;-)

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hariharannkl
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It is very simple, just use the following sql statement,

(DATEDIFF(YY,DOB,GETDATE()) - CASE
WHEN MONTH(DOB)<MONTH(GETDATE()) AND (MONTH(DOB)=MONTH(GETDATE()) OR DAY(DOB)>DAY(GETDATE())) THEN 0 ELSE 1
END)


Here DOB is Columname, and GETDATE() is a function which gives the current date.

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Jeff Moden
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Garadin (1/10/2009)
DECLARE @DOB datetime
SET @DOB = '1/20/1980'

SELECT CASE
WHEN DATEPART(DY,GETDATE()) >= DATEPART(DY,@DOB)
THEN DATEDIFF(YY,@DOB,GETDATE())
ELSE DATEDIFF(YY,@DOB,GETDATE())-1
END



Oh, be careful now. I know this is an old post but the code above doesn't work 100% of the time. For example, it returns "0" years if @DOB = '2000-03-31' and the current date is '2001-03-31'. The problem is that DY contains different values for dates after 28 Feb for ALL leap years.

Try it yourself...

DECLARE @DOB datetime
,@Now datetime
SELECT @DOB = '3/31/2000'
,@Now = '3/31/2001'

SELECT CASE
WHEN DATEPART(DY,@Now) >= DATEPART(DY,@DOB)
THEN DATEDIFF(YY,@DOB,@Now)
ELSE DATEDIFF(YY,@DOB,@Now)-1
END
;




--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
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If you believe that people that were born on the last day of February on a leap year turn a year older on the last day of February on non-leap years, this appears to work although I'll admit that I've not tested very many possibilities.

DECLARE @DOB DATETIME
,@Now DATETIME
SELECT @DOB = '2000-02-29'
,@Now = '2001-02-28'

SELECT DATEDIFF(yy,@DOB,@Now)
- CASE
WHEN @Now < DATEADD(yy,DATEDIFF(yy,@DOB,@Now),@DOB)
THEN 1
ELSE 0
END
;




--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
Jeff Moden
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Group: General Forum Members
Points: 87148 Visits: 41113
math martinez (11/16/2012)

SO HERE ARE THE QUERY

DECLARE @DOB SMALLDATETIME
SELECT @DOB = '11/15/1987'

SELECT
CASE
WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE())
ELSE DATEDIFF(YY,@DOB,GETDATE())-1

END AS AGE

HOPE I CAN HELP! :-)


It also has a Leap Year bug. I changed GETDATE() in your code to @Now to make it simple to test. Notice that your code says a person is 1 year old for the given dates, which is incorrect..

DECLARE @DOB DATETIME
,@Now DATETIME
SELECT @DOB = '2000-03-31'
,@Now = '2001-03-30'

SELECT
CASE
WHEN MONTH(@DOB) >= MONTH(@Now) AND DAY(@DOB) >=DAY(@Now) THEN DATEDIFF(YY,@DOB,@Now)
ELSE DATEDIFF(YY,@DOB,@Now)-1

END AS AGE




--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
Jeff Moden
Jeff Moden
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Group: General Forum Members
Points: 87148 Visits: 41113
hariharannkl (9/7/2013)
It is very simple, just use the following sql statement,

(DATEDIFF(YY,DOB,GETDATE()) - CASE
WHEN MONTH(DOB)<MONTH(GETDATE()) AND (MONTH(DOB)=MONTH(GETDATE()) OR DAY(DOB)>DAY(GETDATE())) THEN 0 ELSE 1
END)


Here DOB is Columname, and GETDATE() is a function which gives the current date.


It would appear that your's also has a Leap Year problem but in the opposite direction. Your's returns "0" for the following dates which is incorrect.


DECLARE @DOB DATETIME
,@Now DATETIME
SELECT @DOB = '2000-03-31'
,@Now = '2001-03-31'

SELECT DATEDIFF(YY,@DOB,@Now) - CASE
WHEN MONTH(@DOB)<MONTH(@Now) AND (MONTH(@DOB)=MONTH(@Now) OR DAY(@DOB)>DAY(@Now)) THEN 0 ELSE 1
END




--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
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