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## Calculating age

 Author Message yogaanand.me SSCrazy Group: General Forum Members Points: 2187 Visits: 177 hi friends i have Date of Birth column in my database , i dont have age columni want to calculate accurate Age form DOB..please help me.. Garadin SSCrazy Group: General Forum Members Points: 2769 Visits: 4107 `DECLARE @DOB datetimeSET @DOB = '1/20/1980'SELECT CASE WHEN DATEPART(DY,GETDATE()) >= DATEPART(DY,@DOB) THEN DATEDIFF(YY,@DOB,GETDATE()) ELSE DATEDIFF(YY,@DOB,GETDATE())-1 END` Seth PhelabaumConsistency is only a virtue if you're not a screwup. ;-)Links: How to Post Sample Data :: Running Totals :: Tally Table :: Cross Tabs/Pivots :: String Concatenation math martinez SSC Rookie Group: General Forum Members Points: 27 Visits: 62 Simple way to compute your age accurately.A lot of query not exactly compute the age? yes! because sometime they only compute the datediff between DOB and datenow and divide it to 365.25 days and as a result they get a number with decimal something like 25 is the age with .06 decimal (age=25.06).In this query you exactly get the age as is it.Example 1DOB = 11/15/1987 and datenow =11/15/2012 the result would be AGE=25 Example 2DOB = 11/14/1987 and datenow =11/15/2012 the result would be AGE=24 SO HERE ARE THE QUERYDECLARE @DOB SMALLDATETIMESELECT @DOB = '11/15/1987'SELECT CASE WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE()) ELSE DATEDIFF(YY,@DOB,GETDATE())-1END AS AGEHOPE I CAN HELP! :-) Phil Parkin SSCoach Group: General Forum Members Points: 18700 Visits: 20451 martinez.math (11/16/2012)Simple way to compute your age accurately.A lot of query not exactly compute the age? yes! because sometime they only compute the datediff between DOB and datenow and divide it to 365.25 days and as a result they get a number with decimal something like 25 is the age with .06 decimal (age=25.06).In this query you exactly get the age as is it.Example 1DOB = 11/15/1987 and datenow =11/15/2012 the result would be AGE=25 Example 2DOB = 11/14/1987 and datenow =11/15/2012 the result would be AGE=24 SO HERE ARE THE QUERYDECLARE @DOB SMALLDATETIMESELECT @DOB = '11/15/1987'SELECT CASE WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE()) ELSE DATEDIFF(YY,@DOB,GETDATE())-1END AS AGEHOPE I CAN HELP! :-)You just responded to a three-year-old post! Help us to help you. For better, quicker and more-focused answers to your questions, consider following the advice in this link.If the answer to your question can be found with a brief Google search, please perform the search yourself, rather than expecting one of the SSC members to do it for you.Please surround any code or links you post with the appropriate IFCode formatting tags. It helps readability a lot. Richard Warr SSCrazy Group: General Forum Members Points: 2796 Visits: 1987 Phil Parkin (11/16/2012)You just responded to a three-year-old post!So, just add 3 to the result and all will be well ;-) _____________________________________________________________________MCSA SQL Server 2012 hariharannkl Forum Newbie Group: General Forum Members Points: 1 Visits: 7 It is very simple, just use the following sql statement,(DATEDIFF(YY,DOB,GETDATE()) - CASE WHEN MONTH(DOB)DAY(GETDATE())) THEN 0 ELSE 1 END)Here DOB is Columname, and GETDATE() is a function which gives the current date. Hariweblog.com Jeff Moden SSC Guru Group: General Forum Members Points: 87148 Visits: 41113 Garadin (1/10/2009)`DECLARE @DOB datetimeSET @DOB = '1/20/1980'SELECT CASE WHEN DATEPART(DY,GETDATE()) >= DATEPART(DY,@DOB) THEN DATEDIFF(YY,@DOB,GETDATE()) ELSE DATEDIFF(YY,@DOB,GETDATE())-1 END`Oh, be careful now. I know this is an old post but the code above doesn't work 100% of the time. For example, it returns "0" years if @DOB = '2000-03-31' and the current date is '2001-03-31'. The problem is that DY contains different values for dates after 28 Feb for ALL leap years.Try it yourself...`DECLARE @DOB datetime ,@Now datetime SELECT @DOB = '3/31/2000' ,@Now = '3/31/2001'SELECT CASE WHEN DATEPART(DY,@Now) >= DATEPART(DY,@DOB) THEN DATEDIFF(YY,@DOB,@Now) ELSE DATEDIFF(YY,@DOB,@Now)-1 END;` --Jeff ModenRBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair Helpful Links:How to post code problemsHow to post performance problemsForum FAQs Jeff Moden SSC Guru Group: General Forum Members Points: 87148 Visits: 41113 If you believe that people that were born on the last day of February on a leap year turn a year older on the last day of February on non-leap years, this appears to work although I'll admit that I've not tested very many possibilities.`DECLARE @DOB DATETIME ,@Now DATETIME SELECT @DOB = '2000-02-29' ,@Now = '2001-02-28' SELECT DATEDIFF(yy,@DOB,@Now) - CASE WHEN @Now < DATEADD(yy,DATEDIFF(yy,@DOB,@Now),@DOB) THEN 1 ELSE 0 END;` --Jeff ModenRBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair Helpful Links:How to post code problemsHow to post performance problemsForum FAQs Jeff Moden SSC Guru Group: General Forum Members Points: 87148 Visits: 41113 math martinez (11/16/2012)SO HERE ARE THE QUERYDECLARE @DOB SMALLDATETIMESELECT @DOB = '11/15/1987'SELECT CASE WHEN MONTH(@DOB) >= MONTH(GETDATE()) AND DAY(@DOB) >=DAY(GETDATE()) THEN DATEDIFF(YY,@DOB,GETDATE()) ELSE DATEDIFF(YY,@DOB,GETDATE())-1END AS AGEHOPE I CAN HELP! :-)It also has a Leap Year bug. I changed GETDATE() in your code to @Now to make it simple to test. Notice that your code says a person is 1 year old for the given dates, which is incorrect..`DECLARE @DOB DATETIME ,@Now DATETIME SELECT @DOB = '2000-03-31' ,@Now = '2001-03-30'SELECT CASE WHEN MONTH(@DOB) >= MONTH(@Now) AND DAY(@DOB) >=DAY(@Now) THEN DATEDIFF(YY,@DOB,@Now) ELSE DATEDIFF(YY,@DOB,@Now)-1END AS AGE` --Jeff ModenRBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair Helpful Links:How to post code problemsHow to post performance problemsForum FAQs Jeff Moden SSC Guru Group: General Forum Members Points: 87148 Visits: 41113 hariharannkl (9/7/2013)It is very simple, just use the following sql statement,(DATEDIFF(YY,DOB,GETDATE()) - CASE WHEN MONTH(DOB)DAY(GETDATE())) THEN 0 ELSE 1 END)Here DOB is Columname, and GETDATE() is a function which gives the current date.It would appear that your's also has a Leap Year problem but in the opposite direction. Your's returns "0" for the following dates which is incorrect.`DECLARE @DOB DATETIME ,@Now DATETIME SELECT @DOB = '2000-03-31' ,@Now = '2001-03-31'SELECT DATEDIFF(YY,@DOB,@Now) - CASE WHEN MONTH(@DOB)DAY(@Now)) THEN 0 ELSE 1 END` --Jeff ModenRBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.First step towards the paradigm shift of writing Set Based code: Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair Helpful Links:How to post code problemsHow to post performance problemsForum FAQs

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