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palindrome


palindrome

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sqlnewbie17
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declare @count int
declare @charvaluefront varchar
declare @charvalueback varchar
declare @frontpos int
declare @backpos int
select @count=len('ABC')
set @frontpos=1
set @backpos=@count
while(@frontpos<=@count)
begin
select @charvaluefront=substring('ABC',@frontpos,1)
select @charvalueback=substring('ABC',@backpos,1)
set @frontpos=@frontpos+1
set @backpos=@backpos-1
print @charvaluefront
print @charvalueback
end

How do I compare @charvaluefront and @charvalueback values to test if the values are equal and print that its a palindrome.
I tried the if clause but it does not work.Any suggestions please
bitbucket-25253
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   declare @count int
declare @charvaluefront varchar
declare @charvalueback varchar
declare @frontpos int
declare @backpos int
select @count=len('ABC')
set @frontpos=1
set @backpos=@count
while(@frontpos<=@count)
begin
select @charvaluefront=substring('ABC',@frontpos,1)
select @charvalueback=substring('abc',@backpos,1)
print substring('abc',@backpos,1) + '**' + substring('ABC',@frontpos,1)
set @frontpos=@frontpos+1
set @backpos=@backpos-1

IF LTRIM(RTRIM(@charvaluefront)) = LTRIM(RTRIM(@charvalueback))
PRINT 'Got them its a palindrome. ' + LTRIM(RTRIM(@charvaluefront))+ ' ' + LTRIM(RTRIM(@charvalueback))
end
Results:
c**A
b**B
Got them its a palindrome. B b
a**C



I would suggest that you post your actual code. The IF statement works as per sample above ....

If everything seems to be going well, you have obviously overlooked something.

Ron

Please help us, help you -before posting a question please read

Before posting a performance problem please read
sqlnewbie17
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This is my IF clause which did not work...
if (@charvaluefront= @charvalueback)
Print 'its a palindrome'

I am not sure why it did not work...
Lynn Pettis
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What are you trying to accomplish?




declare @Str1 varchar(10) = 'ABBA';

if @Str1 = reverse( @Str1)
print @Str1 + ' is a Palindrome'
else
print @Str1 + ' is not a Palindrome'

set @Str1 = 'ABC';

if @Str1 = reverse( @Str1)
print @Str1 + ' is a Palindrome'
else
print @Str1 + ' is not a Palindrome'




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Lynn Pettis

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I do not want to use reverse function.please check the code I posted and correct what wrong I did.thanks
Lynn Pettis
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sqlserver12345 (10/20/2013)
I do not want to use reverse function.please check the code I posted and correct what wrong I did.thanks


And what is wrong with using the reverse function?

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Lynn Pettis

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Lynn Pettis
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And if you must use a loop then how about this?



declare @Str1 varchar(10) = 'ABBA';
declare @IsPalindrome bit = 1;
declare @LoopCnt int = 0;

while @LoopCnt < len(@Str1) and @IsPalindrome = 1
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome'

set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABC';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome'
set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABA';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome'





You will also notice that I short circuit my loop to avoid unnecessary comparisons.

Cool
Lynn Pettis

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Short circuited the loop even more:



declare @Str1 varchar(10) = 'ABBA';
declare @IsPalindrome bit = 1;
declare @LoopCnt int = 0;

while @LoopCnt < len(@Str1) and @IsPalindrome = 1 and (1 + @LoopCnt < len(@Str1) - @LoopCnt)
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome';

set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABC';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1 and (1 + @LoopCnt < len(@Str1) - @LoopCnt)
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome';

set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABA';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1 and (1 + @LoopCnt < len(@Str1) - @LoopCnt)
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome';

set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABACDCABA';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1 and (1 + @LoopCnt < len(@Str1) - @LoopCnt)
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome';

set @LoopCnt = 0;
set @IsPalindrome = 1;
set @Str1 = 'ABACDDCABA';

while @LoopCnt < len(@Str1) and @IsPalindrome = 1 and (1 + @LoopCnt < len(@Str1) - @LoopCnt)
begin
select @IsPalindrome = case when substring(@Str1,1 + @LoopCnt,1) = substring(@Str1,len(@Str1) - @LoopCnt,1) then 1 else 0 end;
set @LoopCnt = @LoopCnt + 1;
end

if @IsPalindrome = 1
print @Str1 + ' is a palindrome'
else
print @Str1 + ' is not a palindrome';




Cool
Lynn Pettis

For better assistance in answering your questions, click here
For tips to get better help with Performance Problems, click here
For Running Totals and its variations, click here or when working with partitioned tables
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sqlserver12345 (10/20/2013)
I do not want to use reverse function.please check the code I posted and correct what wrong I did.thanks


I'm curious... please explain why you don't want to use "REVERSE".

--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
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sqlserver12345 (10/20/2013)
I do not want to use reverse function.please check the code I posted and correct what wrong I did.thanks


I'm curious... please explain why you don't want to use "REVERSE".

I also have to ask what your intended definition of a "palindrome" actually is. For example, the following is a palindrome.

Madam I'm Adam

None of the solutions so far take into account any punctuation or spaces.

Also, do you consider a single letter to be a palindrome?

--Jeff Moden

RBAR is pronounced ree-bar and is a Modenism for Row-By-Agonizing-Row.
First step towards the paradigm shift of writing Set Based code:
Stop thinking about what you want to do to a row... think, instead, of what you want to do to a column.
If you think its expensive to hire a professional to do the job, wait until you hire an amateur. -- Red Adair

Helpful Links:
How to post code problems
How to post performance problems
Forum FAQs
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