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Recursive CTE Example


Recursive CTE Example

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mr.neil.bryan
mr.neil.bryan
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Comments posted to this topic are about the item Recursive CTE Example
Mike Stuart
Mike Stuart
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Neil,

Awesome code - thanks! Still trying to get my head around it - lol.

A suggestion: I was looking for a way to get the manager's name as well as their ID in the results and came up with the following:

1) Set the big boss' Reports_To_ID = to his Employee_ID, instead of null; i.e. change:

INSERT INTO @Employees
SELECT 1,'Roy Hodgson',NULL,'Managing Director'

to

INSERT INTO @Employees
SELECT 1,'Roy Hodgson',1,'Managing Director'


2) Change the final select statement to:

SELECT a.Employee_ID ,
a.Employee_Name ,
a.Reports_To_ID ,
b.Employee_Name Manager_Name,
a.Job_Title
FROM _hirearchy a JOIN _hirearchy b ON b.Employee_ID = a.Reports_To_ID

I've attached my code for your / everyone's benefit to see the changes.


The only problem I see with this is if you change the @BossID to a different value (7248 for Kyle Walker, for example), he doesn't show up in the results as an Employee. Can you think of a way to change your query to return the Manager_Name? That would be awesome!

Kudos again,



Mike



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modified.sql.txt (19 views, 4.00 KB)
Bodhisatya
Bodhisatya
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Crisp. Well written
CGZ
CGZ
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Hello everyone!
Great post!

The only way I've found to get the manager name is changing the table "_hirearchy b" for @Employees in the final select with a left join. It also works with the original insert for the ID 1 with Reports_To_ID = NULL.
I guess this decrease performance or, at least, you lose some of the advantages of using CTE.


FROM _hirearchy a LEFT OUTER JOIN @Employees b ON b.Employee_ID = a.Reports_To_ID




Please, tell me if this is too awful :-P.
Greetings to all!
mr.neil.bryan
mr.neil.bryan
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Awesome thanks Mike!!
Iwas Bornready
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Thanks for the script.
Go


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