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Count all months with "0's" starting today


Count all months with "0's" starting today

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boehnc
boehnc
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Group: General Forum Members
Points: 26 Visits: 100
we are tracking safety events and would like to count the # of consecutive months of 0 events starting from today backward. Maybe I'm overthinking it...but

For example:
Today is September and we had 0 events for Falls, it would be 1,
Today is September and we had 2 events for Falls in September and 0 in August, it would be 0
Today is September and we had 0 events for Falls in September and 0 in August, it would be 2

Select SafetyIndicator, count(safetyevent)
From SafetyEventTable
Group by SafetyIndicator


Would like to have it displayed as:


Indicator, Count
SafetyEvent1, 4
SafetyEvent2, 3
SafetyEvent3, 0
Sean Lange
Sean Lange
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There isn't enough information to provide an answer. In order to help we will need a few things:

1. Sample DDL in the form of CREATE TABLE statements
2. Sample data in the form of INSERT INTO statements
3. Expected results based on the sample data

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dwain.c
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You might want to Google on calendar tables, because I believe you're going to need one to generate a sequence of months back in time as far as you want to look, before you start counting when events did not occur.

As Sean suggested, DDL, consumable sample data and expected results are sure to get you a tested solution.


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SteveEClarke
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Sounds like you need to create a Pivot Table and groupings with a count of number months at zero ....

I will look into an example as this is something already done before.

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Regards
Steve
SQL 2008 DBA/DBD - MCTS/MCITP

Please don't trust me, test the solutions I give you before using them.
ChrisM@Work
ChrisM@Work
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Check if this works. It should generate a count of events per month, including months with no events. If it works then it's a trivial matter to use it as a table source for a query returning your output:

SELECT 
safetyevent,
c.[Month],
[Rows] = COUNT(*)
FROM SafetyEventTable si
RIGHT OUTER JOIN (VALUES (1),(2),(3),(4),(5),(6),(7),(8),(9),(10),(11),(12)) c ([Month])
ON c.[Month] = MONTH(si.[Date])
GROUP BY safetyevent, c.[Month]



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Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden
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