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Effective T-SQL for Median


Effective T-SQL for Median

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dkschill
dkschill
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Is this an effective way to find median?


CREATE TABLE #T (i TINYINT);

GO

INSERT INTO #T
SELECT ABS(CHECKSUM(NEWID())) % 250

GO 1000

;WITH t AS (SELECT i, ROW_NUMBER() OVER (ORDER BY i) AS n, count(*) OVER (PARTITION BY (SELECT NULL)) AS c FROM #T)
SELECT
AVG(i) AS Median
FROM t
WHERE
( c % 2 = 1 AND n = ((c-1)/2)+1 )
OR (c % 2 = 0 AND (n = c / 2 OR n = c / 2 + 1))


Luis Cazares
Luis Cazares
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Last week I came up with this option. I haven't made performace tests. Maybe you could help me with that.


DECLARE @test TABLE(
myint int)
INSERT INTO @test VALUES(1),(2),(3),(4),(5),(6),(7),(8),(9);

WITH CTE AS(
SELECT myint,
NTILE( 2) OVER( ORDER BY myint) tile
FROM @test
)
SELECT CASE WHEN SUM( CASE WHEN tile = 1 THEN 1 END) = SUM( CASE WHEN tile = 2 THEN 1 END)
THEN (MAX( CASE WHEN tile = 1 THEN myint END) + MIN( CASE WHEN tile = 2 THEN myint END))/2.0
ELSE MAX( CASE WHEN tile = 1 THEN myint END) END
FROM CTE




Luis C.
General Disclaimer:
Are you seriously taking the advice and code from someone from the internet without testing it? Do you at least understand it? Or can it easily kill your server?


How to post data/code on a forum to get the best help: Option 1 / Option 2
TheSQLGuru
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Fortunately for you SQL 2012 has much better Windowing Function support. Look into the PERCENTILE_CONT function. I also HIGHLY recommend you purchase Itzik Ben-Gan's SQL Server 2012 High-Performance TSQL Using Window Functions book.

Best,
Kevin G. Boles
SQL Server Consultant
SQL MVP 2007-2012
TheSQLGuru on googles mail service
dkschill
dkschill
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TheSQLGuru (7/30/2013)
Fortunately for you SQL 2012 has much better Windowing Function support. Look into the PERCENTILE_CONT function. I also HIGHLY recommend you purchase Itzik Ben-Gan's SQL Server 2012 High-Performance TSQL Using Window Functions book.


This is awesome thanks!
Alan.B
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dkschill (7/30/2013)
Is this an effective way to find median?


CREATE TABLE #T (i TINYINT);

GO

INSERT INTO #T
SELECT ABS(CHECKSUM(NEWID())) % 250

GO 1000

;WITH t AS (SELECT i, ROW_NUMBER() OVER (ORDER BY i) AS n, count(*) OVER (PARTITION BY (SELECT NULL)) AS c FROM #T)
SELECT
AVG(i) AS Median
FROM t
WHERE
( c % 2 = 1 AND n = ((c-1)/2)+1 )
OR (c % 2 = 0 AND (n = c / 2 OR n = c / 2 + 1))




First and foremost, for your sample data, don't use GO 1000. You will find a tally table works much better for this kind of thing.


WITH t(i) AS (SELECT ROW_NUMBER() OVER (ORDER BY (SELECT 0)) FROM sys.all_objects)
INSERT INTO #T
SELECT ABS(CHECKSUM(NEWID()))%200
FROM t
WHERE i<=1000;



My non-2012 solution is:


;WITH t(i,n,c) AS
( SELECT i,
ROW_NUMBER() OVER (ORDER BY i),
COUNT(*) OVER (PARTITION BY (SELECT NULL))
FROM #T)
SELECT
AVG(i) AS Median
FROM t
WHERE (c%2=1 AND n=((c-1)/2)+1) OR (c%2=0 AND (n=c/2 OR n=c/2+1));



I tested this against Louis' solution (Brilliant use of NTILE BTW) and, though it appears to produce a better query plan (more parallelism, lower est. query cost) it runs about the same speed as what Louis put together (~7 seconds/1 million rows on my crappy test box [4-cpu, 4gb ram test]).

Edit: code formatting messed up.

-- Alan Burstein



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dkschill
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Thanks for your reply! I am always looking to learn more.
Alan.B
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TheSQLGuru (7/30/2013)
Fortunately for you SQL 2012 has much better Windowing Function support. Look into the PERCENTILE_CONT function. I also HIGHLY recommend you purchase Itzik Ben-Gan's SQL Server 2012 High-Performance TSQL Using Window Functions book.


Just an interesting FYI...

I have never used PERCENTILE_CONT but I do have Server 2012 High-Performance TSQL Using Window Functions. With the same sample data from earlier (#T), this is a modified version of Ben-Gan's 2012-based solution using PERCENTILE_COUNT:


WITH t(r,m) AS
( SELECT ROW_NUMBER() OVER(ORDER BY (SELECT NULL)),
PERCENTILE_CONT(0.5) WITHIN GROUP(ORDER BY i) OVER(PARTITION BY NULL)
FROM #T
)
SELECT m AS median
FROM t
WHERE r=1;



Though it is much simpler, Ben-Gan's 2012-PERCENTILE_CONT solution is about twice as slow as any other solution posted thus far. Again, just an FYI.

-- Alan Burstein



Best practices for getting help on SQLServerCentral
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"I can't stress enough the importance of switching from a 'sequential files' mindset to 'set-based' thinking. After you make the switch, you can spend your time tuning and optimizing your queries instead of maintaining lengthy, poor-performing code. " -- Itzek Ben-Gan 2001
dkschill
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Thanks for the example!
Stefan_G
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The original query can be formulated a little bit more elegantly as this:

;WITH t(i,n,c) AS
( SELECT i,
ROW_NUMBER() OVER (ORDER BY i),
COUNT(*) OVER (PARTITION BY (SELECT NULL))
FROM #T)
SELECT
AVG(i) AS Median
FROM t
WHERE 2*n-c BETWEEN 0 AND 2;



This version should be slightly faster because of the simpler expression in the WHERE clause

/SG
Koen Verbeeck
Koen Verbeeck
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TheSQLGuru (7/30/2013)
Fortunately for you SQL 2012 has much better Windowing Function support. Look into the PERCENTILE_CONT function. I also HIGHLY recommend you purchase Itzik Ben-Gan's SQL Server 2012 High-Performance TSQL Using Window Functions book.


+1 great book!


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