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Custom order in SELECT


Custom order in SELECT

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RZ52
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Hi,

How could we change the order in SELECT command based on a custom semicolon delimited phrase.

We have :

[Letters]
----------
a
b
c
d
e

And based on this phrase 'd;c;b;a;e' we want to have :

[Letters]
----------
d
c
b
a
e


Thanks in advance for helps
Erin Ramsay
Erin Ramsay
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Something like this maybe?

select letter from 
(select 'a' letter
   union
select 'b' letter
   union
select 'c' letter
   union      
select 'd' letter
   union   
select 'e' letter)source
order by (case letter when 'd' then 1   when 'c' then 2 when 'b' then 3 when 'a' then 4    when 'e' then 5 end)


RZ52
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Erin Ramsay (3/1/2013)
Something like this maybe?

select letter from 
(select 'a' letter
   union
select 'b' letter
   union
select 'c' letter
   union      
select 'd' letter
   union   
select 'e' letter)source
order by (case letter when 'd' then 1   when 'c' then 2 when 'b' then 3 when 'a' then 4    when 'e' then 5 end)



Dear Erin,

Thanks for suggestion. I think I didn't explain well. what I'm looking for is to run a SELECT against a table based on custom phrase. I have a temp table named @TEST1 like :


DECLARE @TEST1 TABLE (letter varchar(1))
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('b')
INSERT INTO @TEST1(letter) VALUES('c')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('e')



Now I need to "SELECT letter FROM @TEST1" based on order defined in this phrase 'd;c;b;a;e' to have a result like :

[Letters]
----------
d
c
b
a
e

Any idea ?

Thanks
Erin Ramsay
Erin Ramsay
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If your custom phrase is static you can use:

select letter from @test1 order by (case letter when 'd' then 1 when 'c' then 2 when 'b' then 3 when 'a' then 4    when 'e' then 5 end)


RZ52
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Erin Ramsay (3/1/2013)
If your custom phrase is static you can use:

select letter from @test1 order by (case letter when 'd' then 1 when 'c' then 2 when 'b' then 3 when 'a' then 4    when 'e' then 5 end)



Dear Erin,

Thanks, you solved my problem.


Regards.
Sean Lange
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To do this you will first need to parse your delimited string. The easiest way to parse a delimited string like is to use DelimitedSplit8K. You can find out about this splitter by following the article in my signature about splitting strings.

In this case we need to split the string and keep them in order. Here is where we can really harness the power of the DelimitedSplit8K function. The following code should work for you.


DECLARE @TEST1 TABLE (letter varchar(1))
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('b')
INSERT INTO @TEST1(letter) VALUES('c')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('e')

declare @SortString varchar(10) = 'd;c;b;a;e'

select *
from @Test1 t
join
(
   select ItemNumber, Item
   from dbo.DelimitedSplit8K(@SortString, ';')
) x on t.letter = x.Item
order by x.ItemNumber



Make sure you read that article and understand what it is doing.

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Lowell
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ok i just tested this, but i made some assumptions;
when you say "
I THINK you are saying "If I pass this string 'd;c;b;a;e', i want the companies ordered in that order, instead of normal alphabetical order"

If I read that right, then this works correctly. my example is using sys.objects as sample data. so you see Defaults, then check constraints, then foreign keys in that order, for example:

oh yeah, like many good solutions, you need the DelimitedSplit8K function:
http://www.sqlservercentral.com/articles/Tally+Table/72993/


select * from sys.objects
OUTER apply master.dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
ORDER BY CASE WHEN LEFT(name,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber




Lowell

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help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!

Sean Lange
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Lowell, you would have to add a where clause to only return those rows that match. Notice below this will return a cartesian product.


select *
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber



The top 5 rows are sorted perfectly but it returned 25 rows instead of 5.

Add the where clause and it works correctly.


select *
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
where t.letter = myfn.Item
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber



_______________________________________________________________

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Cross Tabs and Pivots, Part 1 – Converting Rows to Columns
Cross Tabs and Pivots, Part 2 - Dynamic Cross Tabs
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Understanding and Using APPLY (Part 2)
RZ52
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Sean Lange (3/1/2013)
Lowell, you would have to add a where clause to only return those rows that match. Notice below this will return a cartesian product.


select *
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber



The top 5 rows are sorted perfectly but it returned 25 rows instead of 5.

Add the where clause and it works correctly.


select *
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
where t.letter = myfn.Item
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber



Dear Sean,

The proposed command works well. However, if we have repeated value of same letter like :


DECLARE @TEST1 TABLE (letter varchar(1))
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('b')
INSERT INTO @TEST1(letter) VALUES('c')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('d')



running the command


select letter
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
where t.letter = myfn.Item
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber



will return all rows. I tried to add SELECT DISTINCT to above command :


Select Distinct Letter from
(select letter
from @Test1 t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
where t.letter = myfn.Item
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber) xx



But it raise the error :


Msg 1033, Level 15, State 1, Line 16
The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified.


How could I manage to avoid repeated values ?

Thanks
dwain.c
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Try it like this:


DECLARE @TEST1 TABLE (letter varchar(1))
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('b')
INSERT INTO @TEST1(letter) VALUES('c')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('a')
INSERT INTO @TEST1(letter) VALUES('d')
INSERT INTO @TEST1(letter) VALUES('d')

;WITH CTE AS (SELECT DISTINCT letter FROM @Test1)
select letter
from CTE t
OUTER apply dbo.delimitedsplit8k('d;c;b;a;e',';') myfn
where t.letter = myfn.Item
ORDER BY CASE WHEN LEFT(letter,1) = myfn.Item THEN 1 ELSE 2 END,myfn.ItemNumber





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