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query to count repating alphabet in a string


query to count repating alphabet in a string

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saltpepo
saltpepo
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declare @asd varchar(20)
set @asd ='asdaaaadffa'
Lowell
Lowell
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saltpepo (9/21/2012)
declare @asd varchar(20)
set @asd ='asdaaaadffa'


so do you want a count of the max number of repeats in the string for each letter?
so a=4,s=1,d=1,f=2, or are you after just a single letter?
or the count of all the 'a''s which would be 6?

Lowell
--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!
saltpepo
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Hello,
I need to count repeating alphabet only
a=6 thats it.
Mark Cowne
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declare @asd varchar(20)
set @asd ='asdaaaadffa'
select len(@asd) - len(replace(@asd,'a',''))



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Lowell
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saltpepo (9/21/2012)
Hello,
I need to count repeating alphabet only
a=6 thats it.


well, 'f' repeats as well in your example.
the easiest way for the count is simply

SELECT LEN(@asd) - LEN(REPLACE(@asd,'a',''))



Lowell
--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!
Lowell
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Mark-101232 (9/21/2012)

declare @asd varchar(20)
set @asd ='asdaaaadffa'
select len(@asd) - len(replace(@asd,'a',''))


oh your fast on the draw there, partner!

Lowell
--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!
saltpepo
saltpepo
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Cool Guys u rock.
Could you give some good links to learn sql basics
Mark Cowne
Mark Cowne
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Lowell (9/21/2012)
Mark-101232 (9/21/2012)

declare @asd varchar(20)
set @asd ='asdaaaadffa'
select len(@asd) - len(replace(@asd,'a',''))


oh your fast on the draw there, partner!


Yee-Haa!

____________________________________________________

Deja View - The strange feeling that somewhere, sometime you've optimised this query before

How to get the best help on a forum

http://www.sqlservercentral.com/articles/Best+Practices/61537




Lowell
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saltpepo (9/21/2012)
Cool Guys u rock.
Could you give some good links to learn sql basics


a lot of great guys here have put together a bunch of "stairways" series on many of the SQL subjects that give great step by steps and walk throughs;
take a look here:
SQL Server Stairways Atricles

there's one that starts with t-SQL basics, and many on specific usages;
Stairway to TSQL DML

Lowell
--help us help you! If you post a question, make sure you include a CREATE TABLE... statement and INSERT INTO... statement into that table to give the volunteers here representative data. with your description of the problem, we can provide a tested, verifiable solution to your question! asking the question the right way gets you a tested answer the fastest way possible!
ChrisM@Work
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Big hammer;

DECLARE @asd VARCHAR(20)
SET @asd = 'asdaaaadffa'

SELECT
Letter,
Occurrences = COUNT(*)
FROM (
SELECT Letter = SUBSTRING(@asd,n,1)
FROM (SELECT TOP(LEN(@asd)) n = ROW_NUMBER() OVER (ORDER BY (SELECT NULL))
FROM sys.all_columns) tally
) d
GROUP BY Letter
ORDER BY Occurrences DESC



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