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Function to get number of days in month


Function to get number of days in month

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harsha.majety
harsha.majety
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Comments posted to this topic are about the item Function to get number of days in month
Obs
Obs
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How is this not better?

Select day(dateadd(mm,DateDiff(mm, -1, getdate()),0) -1)



harsha.majety
harsha.majety
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Thats clever.
Toby Harman
Toby Harman
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My personal favourite

SELECT
DATEPART(dd, DATEADD(dd, DATEPART(dd, DATEADD(mm, 1, @day)) * -1, DATEADD(mm, 1, @day)))



I suspect you would be hard pressed to notice the difference between any of the above, though the Client Statistics suggests the CASE solution is the most efficient
Mitesh Oswal
Mitesh Oswal
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DECLARE @dtDate DATETIME

SET @dtDate = '2011/02/28'
SELECT @dtDate= dateadd(mm,datediff(mm,0,@dtDate),0)
SELECT datediff(dd,@dtDate,dateadd(mm,1,@dtDate))




Regards,
Mitesh OSwal
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How about this?

RETURN DAY(DATEADD(d,-1,DATEADD(mm,DATEDIFF(m,0,@day)+1,0)))
SanDroid
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Here is some psuedo code for a correct leap year test calculation.

if year modulo 400 is 0
then is_leap_year
else if year modulo 100 is 0
then not_leap_year
else if year modulo 4 is 0
then is_leap_year
else
not_leap_year

Since this, and other date checking code, is built into the TSQL Date functions I recomend using the examples that have already been posted.
Stephen_W_Dodd
Stephen_W_Dodd
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Well, since everyone else likes to do subtractions, I thought I'd contribute an addition only solution :-D (if you don't count DATEDIFF as subtraction :-))

SELECT DATEDIFF(dd,@testdate,(DATEADD(m,1,@testdate)))


Slope
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Of course, if you use a calendars table you never have to worry about having to code or validate any date calculations ever again. :-P Sure makes life a lot simpler. Here is how I would get that answer:


SELECT d.DaysInCalendarMonth
FROM dbo.dwCalendars d
WHERE d.CalendarDate = @SomeDate


Subramaniyan.Manickam
Subramaniyan.Manickam
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nice one..:-)
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