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UMG Developer
UMG Developer
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Bradley Deem (3/22/2011)
UMG Developer (3/21/2011)
Interesting question, thanks, and a good reason you should always specify the data type for hardcoded items in the first set of values or in the first query when using UNION.


I'm not sure this is true. It looks to me Data Type Precendence determines the data type not the order in the UNION or VALUES clause. Consider the following.


Bradley,

Thanks for pointing that out, of course I should have known better. Here is a link to the Table Value Constructor in BOL that mentions the data type precedence: http://msdn.microsoft.com/en-us/library/dd776382.aspx
Bradley Deem
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Great question.

UMG,

Thanks for the link, that's good to know for sure.
SQLRNNR
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thanks for the question



Jason AKA CirqueDeSQLeil
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M&M
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This question is worth more than a point :-D

M&M
Gopi S
Gopi S
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Bradley,
You are right. The datatype is determined by the order of precedence as explained in http://msdn.microsoft.com/en-us/library/ms190309.aspx . Thanks for pointing out this and i apologize everyone for making this mistake.
We can verify this by small example.

For integer datatype the order of precedence level is
1: bigint (highest precedence)
2: int
3: smallint
4: tinyint (lowest precedence) .
Note: For demo i have choosen only the above 4 datatype.

After running the below code Go to
DataBases -> SystemDataBases -> tempdb -> TestTable -> Columns . Its clear that column C1 is created with type bigint and C2 is created with type int based on the highest precedence in the select list.

-- Sample code
use tempdb
go

select * into TestTable from
(
select CAST(1 as smallint) as C1, CAST(6 as smallint) as C2
union
select CAST(2 as tinyint),CAST(6 as int)
union
select CAST(3 as bigint),CAST(6 as smallint)
union
select CAST(4 as int),CAST(6 as tinyint)
) T

Thanks again.

Gopi
pksutha
pksutha
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Hi Gopi,

select * into TestTable from
(
select CAST(1 as smallint) as C1, CAST(6 as smallint) as C2
union
select CAST(2 as tinyint),CAST(6 as int)
union
select CAST(3 as bigint),CAST(6 as smallint)
union
select CAST(4 as int),CAST(6 as tinyint)
) T


Note: Good only....

But u've given only these are the orderwise datatype based on size . but i need how i can come to know query wise.. plz will u give example and we must see the difference in that example visually.
Gopi S
Gopi S
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I am sorry i couldn't get your question. Can you pls explain you question in detail.
Thanks
pksutha
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Hi Gopi,

select * into TestTable from
(
select CAST(1 as smallint) as C1, CAST(6 as smallint) as C2
union
select CAST(2 as tinyint),CAST(6 as int)
union
select CAST(3 as bigint),CAST(6 as smallint)
union
select CAST(4 as int),CAST(6 as tinyint)
) T

Note: Practically i want to see the difference... will u give example for that..
Gopi S
Gopi S
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As mentioned earlier, after executing the above code,
Go to
DataBases -> SystemDataBases -> tempdb -> TestTable -> Columns .

You can see that column C1 is created with type bigint and C2 is created with type int based on the highest precedence in the select list.

I think this could be the practical example you are expecting.

Thanks
Gopi
Koen Verbeeck
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Nice question, thanks.


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