SQLServerCentral » SQL Server 2008 - General » Recursive function - sql2008InstantForum 2016-2 FinalSQLServerCentralhttps://www.sqlservercentral.com/Forums/SQLServerCentralWed, 18 Jan 2017 03:38:53 GMT20Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370081.aspxHi,
I am new to sql server 2008 functions, I am facing an issue and request, if some can help.
I have a table like
id_task id_fathertask level_task duracion_task percent_task name_task
1 1 1 76 NULL Task 1
2 1 2 60 NULL Task 1.1
3 2 3 2 100 Task 1.1.1
4 2 3 38 NULL Task 1.1.2
5 4 4 10 100 Task 1.1.2.1
6 4 4 22 20 Task 1.1.2.2
7 4 4 5 35 Task 1.1.2.3
8 4 4 1 40 Task 1.1.2.4
9 2 3 20 NULL Task 1.1.3
10 9 4 20 20 Task 1.1.3.1
11 1 2 9 NULL Task 1.2
12 11 3 2 0 Task 1.2.1
13 11 3 7 NULL Task 1.2.2
14 13 4 2 50 Task 1.2.2.1
15 13 4 5 50 Task 1.2.2.2
16 1 2 10 0 Task 1.3
17 1 2 20 0 Task 1.4
18 1 2 6 NULL Task 1.5
19 18 3 6 NULL Task 1.5.1
20 19 4 6 NULL Task 1.5.1.1
21 20 5 6 10 Task 1.5.1.1.1
I am trying to create a recurive function.
Calculation starts from the bottom
(5*6)+10 = 40
it goes for the column above this percent_task column
then
4+(6*65)
until the name_task is same (untill 1.5, starting from 1.5.1... to 1.5)
when it changes 1.4..then new caluculation
and at the end we need to do the sum
sum of ( 1.5+ 1.4+1.3.....like that..
I am trying to create a recursive function, but no luck.
Create function [dbo].[test1](@p_id_task int)
RETURNS @output TABLE(data VARCHAR(256))
begin
declare @i int
while @i in ( select top 100 id_task from [dbo].[test1](@p_id_task) where id_task<=@p_id_task and id_fathertask>=1 and status is null
order by id_task desc
)
begin
DECLARE @start INT
select @start = (level_task*duracion_task)+ COALESCE(percent_task,0) from [Reportes].[dbo].[FunctionTST1] where status='Processed' and
id_task=@i and status is null
INSERT INTO @output (data) values (@start)
end
return
end
Can anyone help me on this?
Tue, 16 Oct 2012 12:26:47 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1373462.aspxI found the solution and it is working fine. Still to undergo testing. But I think, it is works as expected.
Tue, 16 Oct 2012 12:26:47 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1373418.aspxHi,
Did you understand the calculation.
Does anyone has any approch for this calculation?
Tue, 16 Oct 2012 11:10:47 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372374.aspxYes, calcuation has changed from the first post. I did not understand lmm_value means. Yes the values are from MS-Project.
The value of Task 1 is obtained from its children - Task 1.1, Task 1.2, Task 1.3, Task 1.4 and Task 1.5. All these task has the id_father = 1 and Task 1 has id_task = 1. Hence all these 5 are the children of Task 1.
(38*60+39*9+0*10+0*20+10*6)/(60+9+10+20+6)
2691/105 = 25
To find the value of Task 1.1, we need to calculate from its children - task 1.1.1, task 1.1.2, task 1.1.3
(100*2+44*38+20*20)/(2+38+20) = 38
For ex. Task 1.5 has only one child task 1.5.1 and task 1.5.1 has one children task 1.5.1.1 and task 1.5.1.1 has one children task 1.5.1.1.1. First we need to calculate the value of 1.5.1.1.1 that is 10*6/10 = 10 and this values with be precent_task for its parent task 1.5.1.1 and the values of task 1.5.1.1 will 10*6/6=10 and goes on. Let me know, if this is clear.
But I have developed the proceure, it is working almost fine. But, when I debug and check the values, it calulated fine for the first loop and from next loop onwards, the value of Calc and calc1 variables dont change, they remain 0. I dont understand wny this is happening. Here is the code.
create Procedure GetCalculationForTestData1
(
@taskId int,
@fatherId int,
@taskLevel int
)
as begin
Create table #TestFinal
(
id_task int primary key,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24),
Calculation int,
Calculation1 int
);
Insert #TestFinal (id_task, id_fathertask, level_task, duracion_task, percent_task, name_task)
select id_task, id_fathertask, level_task, duracion_task, percent_task, name_task
from [Reportes].[dbo].[FunctionTST1]
declare @Calc int = 0
declare @Calc1 int = 0
declare @IdFat int =0
While(@fatherId <> 0)
Begin
While(@taskLevel <> 0)
Begin
Create table #TestData
(
id_task int primary key,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24),
Calculation int,
Calculation1 int
);
Insert #TestData (id_task, id_fathertask, level_task, duracion_task, percent_task, name_task)
select id_task, id_fathertask, level_task, duracion_task, percent_task, name_task
from [Reportes].[dbo].[FunctionTST1]
where level_task = @taskLevel and id_fathertask = @fatherId
;with cteOrdered as
(
select * from #TestData
)
update cteOrdered
set @Calc = Calculation = (percent_task * duracion_task)
from cteOrdered WITH (TABLOCKX)
OPTION (MAXDOP 1)
;with cteOrdered1 as
(
select * from #TestData
)
update cteOrdered1
set @Calc1 = Calculation1= ((select sum(Calculation) from cteOrdered1) / (select sum(duracion_task) from cteOrdered1))
set rowcount 1
select @IdFat = id_fathertask from #TestData
set rowcount 1000
update #TestFinal set percent_task = @Calc1 where id_task = @IdFat
drop table #TestData
set @taskLevel = @taskLevel -1
set @Calc = 0
set @Calc1 = 0
End
set @fatherId = @fatherId - 1
set @Calc = 0
set @Calc1 = 0
End
select * from #TestFinal
End
Fri, 12 Oct 2012 15:29:41 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372321.aspxYour calculation seems have changed since your first post?
[quote]
21 20 5 6 10 Task 1.5.1.1.1
I am trying to create a recurive function.
Calculation starts from the bottom
(5*6)+10 = 40
it goes for the column above this percent_task column
[/quote]
But now in your expected output you have lmm_value as 10???
There is something fundamentally wrong with this whole process. Your id_task has a father of itself which is a bit challenging. The more I am looking at this the more this seems like something exported from MS-Project where Task 1 is the main task and all the rest of them are sub tasks? Unfortunately it is totally unclear to me what you want for output. Obviously I can see the values but I don't understand how you calculate them, and they have changed somewhere along the way.
Can you explain clearly how you get your calculation? Also I am not quite sure how you would get the 25.37 as the output of your proc?? Maybe you just need to approach this differently. I would try something but I have clue what the final value means or how to get it.Fri, 12 Oct 2012 12:32:07 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372277.aspxThanks a lot for coming forward to help. I really appreciate that. Here are the insert statements. And the values I pass to procedure is (21,20,5). Please let me know, if need any other details.
CREATE TABLE [dbo].[test](
[id_task] [int] NULL,
[id_fathertask] [int] NULL,
[level_task] [int] NULL,
[duracion_task] [float] NULL,
[percent_task] [float] NULL,
[name_task] [nvarchar](50) NULL,
[Imm_value] [int] Null
);
insert into [dbo].[test]
values
(1,1,1,76,NULL,'Task 1',25),
(2,1,2,60,NULL,'Task,1.1',38),
(3,2,3,2,100,'Task,1.1.1',100),
(4,2,3,38,NULL,'Task,1.1.2',44),
(5,4,4,10,100,'Task,1.1.2.1',100),
(6,4,4,22,20,'Task,1.1.2.2',20),
(7,4,4,5,35,'Task,1.1.2.3',35),
(8,4,4,1,40,'Task,1.1.2.4',40),
(9,2,3,20,NULL,'Task,1.1.3',20),
(10,9,4,20,20,'Task,1.1.3.1',20),
(11,1,2,9,NULL,'Task,1.2',39),
(12,11,3,2,0,'Task,1.2.1',0),
(13,11,3,7,NULL,'Task,1.2.2',50),
(14,13,4,2,50,'Task,1.2.2.1',50),
(15,13,4,5,50,'Task,1.2.2.2',50),
(16,1,2,10,0,'Task,1.3',0),
(17,1,2,20,0,'Task,1.4',0),
(18,1,2,6,NULL,'Task,1.5',10),
(19,18,3,6,NULL,'Task,1.5.1',10),
(20,19,4,6,NULL,'Task,1.5.1.1',10),
(21,20,5,6,10,'Task,1.5.1.1.1',10);
Fri, 12 Oct 2012 10:41:16 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372275.aspxNow, I am thinking, the correct way is to pass the paramenters for Heighest id_father and its corresponding Id_task and level_task.Fri, 12 Oct 2012 10:31:38 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372270.aspxOK one more time, can you post this as inserts to a temp table so I can actually read it? And again what are the values you would pass in to the procedure that you created? Not an explanation because I don't know what "highest" means. What would be the actual values? I am willing to help but you have to help me understand your situation.Fri, 12 Oct 2012 10:27:43 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372268.aspxSorry, I accidently posted without comments.
the last value in the each row is the intermediate result. In the procedure I will pass the parameters as Heighest level and its id_father and id_task. First one is id_task next is id_father and level_task(heighest level available in the tree).
like 21, 20, 5 from the table.Fri, 12 Oct 2012 10:25:44 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372265.aspxid_task id_fathertask level_task duracion_task percent_task name_task
1 1 1 76 NULL Task 1 25
2 1 2 60 NULL Task 1.1 38
3 2 3 2 100 Task 1.1.1 100
4 2 3 38 NULL Task 1.1.2 44
5 4 4 10 100 Task 1.1.2.1 100
6 4 4 22 20 Task 1.1.2.2 20
7 4 4 5 35 Task 1.1.2.3 35
8 4 4 1 40 Task 1.1.2.4 40
9 2 3 20 NULL Task 1.1.3 20
10 9 4 20 20 Task 1.1.3.1 20
11 1 2 9 NULL Task 1.2 39
12 11 3 2 0 Task 1.2.1 0
13 11 3 7 NULL Task 1.2.2 50
14 13 4 2 50 Task 1.2.2.1 50
15 13 4 5 50 Task 1.2.2.2 50
16 1 2 10 0 Task 1.3 0
17 1 2 20 0 Task 1.4 0
18 1 2 6 NULL Task 1.5 10
19 18 3 6 NULL Task 1.5.1 10
20 19 4 6 NULL Task 1.5.1.1 10
21 20 5 6 10 Task 1.5.1.1.1 10
Fri, 12 Oct 2012 10:20:53 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372261.aspxCan you post the table with the intermediate amounts? It is very unclear what you are trying to do here. Given the procedure you created what would be the values you pass in?Fri, 12 Oct 2012 10:08:57 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372258.aspxFinal result should be 25 or 25.37 to be precise. This the sample table data. Task is calulate the value of root of the tree that is Task1(First row) by using its children. For Ex. thirs row id_task=3 it is unique for every row and identify the task number. level_task = 3, that is it belongs to the third level in the tree. id_fathertask = 2 means, its parent the one which has id_task as 2, that is Task 1.1(second row). The result of the calculation should go to the percent_task of their parent. Hence we start the calculation from the lowest level in the tree and result goes to its parent and finally we find the value of the root.
id_task id_fathertask level_task duracion_task percent_task name_task
1 1 1 76 NULL Task 1
2 1 2 60 NULL Task 1.1
3 2 3 2 100 Task 1.1.1
4 2 3 38 NULL Task 1.1.2
5 4 4 10 100 Task 1.1.2.1
6 4 4 22 20 Task 1.1.2.2
7 4 4 5 35 Task 1.1.2.3
8 4 4 1 40 Task 1.1.2.4
9 2 3 20 NULL Task 1.1.3
10 9 4 20 20 Task 1.1.3.1
11 1 2 9 NULL Task 1.2
12 11 3 2 0 Task 1.2.1
13 11 3 7 NULL Task 1.2.2
14 13 4 2 50 Task 1.2.2.1
15 13 4 5 50 Task 1.2.2.2
16 1 2 10 0 Task 1.3
17 1 2 20 0 Task 1.4
18 1 2 6 NULL Task 1.5
19 18 3 6 NULL Task 1.5.1
20 19 4 6 NULL Task 1.5.1.1
21 20 5 6 10 Task 1.5.1.1.1
Fri, 12 Oct 2012 10:00:27 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372222.aspx[quote][b]sqlSer12 (10/12/2012)[/b][hr]Table looks like below. For Ex. row 3, Id_task = 3, level_task=3 menas it is at level 3, id_fathertask = 2 that means, its parent is the one which has id_task=2, that is the one in the second row and so on. Aim is to calculate the value of the root that is Task 1. The value of Task 1 should be 25 after calculations.
It is kind of project plan and differnt level and sub level inside. id_task is kind of a primary key.
id_task id_fathertask level_task duracion_task percent_task name_task
1 1 1 76 NULL Task 1
2 1 2 60 NULL Task 1.1
3 2 3 2 100 Task 1.1.1
4 2 3 38 NULL Task 1.1.2
5 4 4 10 100 Task 1.1.2.1
6 4 4 22 20 Task 1.1.2.2
7 4 4 5 35 Task 1.1.2.3
8 4 4 1 40 Task 1.1.2.4
9 2 3 20 NULL Task 1.1.3
10 9 4 20 20 Task 1.1.3.1
11 1 2 9 NULL Task 1.2
12 11 3 2 0 Task 1.2.1
13 11 3 7 NULL Task 1.2.2
14 13 4 2 50 Task 1.2.2.1
15 13 4 5 50 Task 1.2.2.2
16 1 2 10 0 Task 1.3
17 1 2 20 0 Task 1.4
18 1 2 6 NULL Task 1.5
19 18 3 6 NULL Task 1.5.1
20 19 4 6 NULL Task 1.5.1.1
21 20 5 6 10 Task 1.5.1.1.1
[/quote]
I want to know what you want as output from your query. And to make it legible inserting into a temp table will make it a lot easier to deal with.
Fri, 12 Oct 2012 09:17:28 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372186.aspxTable looks like below. For Ex. row 3, Id_task = 3, level_task=3 menas it is at level 3, id_fathertask = 2 that means, its parent is the one which has id_task=2, that is the one in the second row and so on. Aim is to calculate the value of the root that is Task 1. The value of Task 1 should be 25 after calculations.
It is kind of project plan and differnt level and sub level inside. id_task is kind of a primary key.
id_task id_fathertask level_task duracion_task percent_task name_task
1 1 1 76 NULL Task 1
2 1 2 60 NULL Task 1.1
3 2 3 2 100 Task 1.1.1
4 2 3 38 NULL Task 1.1.2
5 4 4 10 100 Task 1.1.2.1
6 4 4 22 20 Task 1.1.2.2
7 4 4 5 35 Task 1.1.2.3
8 4 4 1 40 Task 1.1.2.4
9 2 3 20 NULL Task 1.1.3
10 9 4 20 20 Task 1.1.3.1
11 1 2 9 NULL Task 1.2
12 11 3 2 0 Task 1.2.1
13 11 3 7 NULL Task 1.2.2
14 13 4 2 50 Task 1.2.2.1
15 13 4 5 50 Task 1.2.2.2
16 1 2 10 0 Task 1.3
17 1 2 20 0 Task 1.4
18 1 2 6 NULL Task 1.5
19 18 3 6 NULL Task 1.5.1
20 19 4 6 NULL Task 1.5.1.1
21 20 5 6 10 Task 1.5.1.1.1
Fri, 12 Oct 2012 08:39:57 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1372143.aspxCan you post what you want for desired output? Just create a temp table and hard code inserts into it. I can't understand your explanation very well and the data just has me scratching me head.Fri, 12 Oct 2012 07:55:56 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1371884.aspxThank you so much for your response. I am sorry for changing the code.
I cannot combine two update statements, since I need the first update value to calculate the next one.
Here is the code and the logic which I am using.
CREATE TABLE [dbo].[FunctionTST1](
[id_task] [int] NULL,
[id_fathertask] [int] NULL,
[level_task] [int] NULL,
[duracion_task] [float] NULL,
[percent_task] [float] NULL,
[name_task] [nvarchar](50) NULL
);
insert into [dbo].[FunctionTST1]
values
(1,1,1,76,NULL,'Task 1'),
(2,1,2,60,NULL,'Task,1.1'),
(3,2,3,2,100,'Task,1.1.1'),
(4,2,3,38,NULL,'Task,1.1.2'),
(5,4,4,10,100,'Task,1.1.2.1'),
(6,4,4,22,20,'Task,1.1.2.2'),
(7,4,4,5,35,'Task,1.1.2.3'),
(8,4,4,1,40,'Task,1.1.2.4'),
(9,2,3,20,NULL,'Task,1.1.3'),
(10,9,4,20,20,'Task,1.1.3.1'),
(11,1,2,9,NULL,'Task,1.2'),
(12,11,3,2,0,'Task,1.2.1'),
(13,11,3,7,NULL,'Task,1.2.2'),
(14,13,4,2,50,'Task,1.2.2.1'),
(15,13,4,5,50,'Task,1.2.2.2'),
(16,1,2,10,0,'Task,1.3'),
(17,1,2,20,0,'Task,1.4'),
(18,1,2,6,NULL,'Task,1.5'),
(19,18,3,6,NULL,'Task,1.5.1'),
(20,19,4,6,NULL,'Task,1.5.1.1'),
(21,20,5,6,10,'Task,1.5.1.1.1');
The actual result is 25.37 and if convert into whole numbers during all the calclulations then it is 25.
The aim of this is to find the percent_task for task1. Table is kind of a tree with Task1 as the root. Task one has 5 children Task 1.1, Task 1.2, Task 1.3, Task 1.4 and Task 1.5. Task 1.5 has one child Task 1.5.1 and it has one child Task 1.5.1.1. And Task 1.5.1.1 has one child Task 1.5.1.1.1 and so on.
Task 1.1.2 has four children Task 1.1.2.1, Task 1.1.2.2, Task 1.1.2.3 and Task 1.1.2.4. and so on in the table.
We need to start calculation from the leaf nodes. and result of the calulation replaces the percent_task of its parent.
For example to calculate percent_task for Task 1.1.2, we need to use the value of his children.
10*100 = 1000
22*20 = 440
5*35 = 175
1*40 = 40
-- ---------
38 1655
1655/38 = 43.55(44) = percent_task of task 1.1.2
Hence the values of Task 1.1 = 38, Task 1.2 = 38.8, Task 1.3 = 0, Task 1.4 = 0 and Task 1.5 = 10 and final value is 25
Hope the above one is understandable. I do not have much exp in this. Hence I developed the code from whatever you pasted and googling.Thu, 11 Oct 2012 22:23:09 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1371876.aspxI am guessing that you didn't read through the article I suggested and understand this code. You can't reference the cte by multiple statements after it is declared. You need to combine your two update statements. I noticed you also removed the order by in the cte. This order is MANDATORY or you don't know what order the results will be returned. And why oh why did you put this into nested while loops??? You totally destroyed any chance at making this remotely quick. You need to start over here.
Can you post ddl (create table scripts), sample data (insert statements) and desired output based on your sample data? There is no need to put this in nested loops.Thu, 11 Oct 2012 21:21:34 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1371838.aspxThanks a lot. However, the requirement got changed and had to modify the procedure. This is the proc
alter Procedure GetCalculationForTestData
(
@taskId int,
@fatherId int,
@taskLevel int
)
as begin
Create table #TestFinal
(
id_task int primary key,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24),
Calculation int,
Calculation1 int
);
Insert #TestFinal (id_task, id_fathertask, level_task, duracion_task, percent_task, name_task)
select id_task, id_fathertask, level_task, duracion_task, percent_task, name_task
from [Reportes].[dbo].[FunctionTST1]
While(@fatherId <> 0)
Begin
While(@taskLevel <> 0)
Begin
Create table #TestData
(
id_task int primary key,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24),
Calculation int,
Calculation1 int
);
Insert #TestData (id_task, id_fathertask, level_task, duracion_task, percent_task, name_task)
select id_task, id_fathertask, level_task, duracion_task, percent_task, name_task
from [Reportes].[dbo].[FunctionTST1]
where level_task = @taskLevel and id_fathertask = @fatherId
declare @Calc int = 0
declare @Calc1 int = 0
declare @temp int = 0
;with cteOrdered as
(
select * from #TestData
)
update cteOrdered
set @Calc = Calculation = (percent_task * duracion_task)
from cteOrdered WITH (TABLOCKX)
OPTION (MAXDOP 1)
update cteOrdered
set @Calc1 = Calculation1 = sum(Calculation)/sum(duracion_task)
from cteOrdered WITH (TABLOCKX)
OPTION (MAXDOP 1)
update #TestFinal set percent_task = @Calc1 where @taskId = @fatherId
drop table #TestData
set @temp = @taskLevel -1
execute GetCalculationForTestData1 @taskId,@fatherId,@temp
End
set @temp=0
set @temp = @fatherId - 1
execute GetCalculationForTestData1 @taskId,@temp,@taskLevel
End
select * from #TestFinal
End
But I am having one error on line 62. Invalid object name 'cteOrdered'. Can anyone help me to solve this?Thu, 11 Oct 2012 17:54:30 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370523.aspx[quote][b]sqlSer12 (10/9/2012)[/b][hr]Thanks, I am going through your link.
But we can pass the parameter for the function.[/quote]
I put together an example of this using the quirky update method. Since you never posted any ddl or sample data I used what Lynn posted.
The code below works on the example you provided. I also tried for Task,1.2.2 but I have no idea if it does what you want.
[code]
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[TestData]') AND type in (N'U'))
DROP TABLE [dbo].TestData
GO
IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'[dbo].[GetCalculationForTestData]') AND type in (N'P'))
DROP PROCEDURE [dbo].[GetCalculationForTestData]
go
Create table dbo.TestData (
id_task int,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24)
);
go
insert into dbo.TestData
values
(1,1,1,76,NULL,'Task 1'),
(2,1,2,60,NULL,'Task,1.1'),
(3,2,3,2,100,'Task,1.1.1'),
(4,2,3,38,NULL,'Task,1.1.2'),
(5,4,4,10,100,'Task,1.1.2.1'),
(6,4,4,22,20,'Task,1.1.2.2'),
(7,4,4,5,35,'Task,1.1.2.3'),
(8,4,4,1,40,'Task,1.1.2.4'),
(9,2,3,20,NULL,'Task,1.1.3'),
(10,9,4,20,20,'Task,1.1.3.1'),
(11,1,2,9,NULL,'Task,1.2'),
(12,11,3,2,0,'Task,1.2.1'),
(13,11,3,7,NULL,'Task,1.2.2'),
(14,13,4,2,50,'Task,1.2.2.1'),
(15,13,4,5,50,'Task,1.2.2.2'),
(16,1,2,10,0,'Task,1.3'),
(17,1,2,20,0,'Task,1.4'),
(18,1,2,6,NULL,'Task,1.5'),
(19,18,3,6,NULL,'Task,1.5.1'),
(20,19,4,6,NULL,'Task,1.5.1.1'),
(21,20,5,6,10,'Task,1.5.1.1.1');
go
create Procedure GetCalculationForTestData
(
@TaskName varchar(50)
)
as begin
Create table #TestData
(
id_task int primary key, --MUST have a clustered index for the running total to work
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24),
Calculation int --need to store the calculation so we added this extra column
);
Insert #TestData (id_task, id_fathertask, level_task, duracion_task, percent_task, name_task)
select id_task, id_fathertask, level_task, duracion_task, percent_task, name_task
from TestData
where name_task like @TaskName + '%'
declare @Calc int = 0
;with cteOrdered as
(
select top 2147483648 *
from #TestData
order by id_fathertask desc
)
update cteOrdered
set @Calc = Calculation = (level_task * duracion_task) + isnull(percent_task, @Calc)
from cteOrdered WITH (TABLOCKX)
OPTION (MAXDOP 1)
select * from #TestData
order by id_fathertask desc
end
go
exec GetCalculationForTestData @TaskName = 'Task,1.2.2'
exec GetCalculationForTestData @TaskName = 'Task,1.5'
[/code]
If you use this make sure you read the running totals article I referenced and understand what it is doing. You are the one who is going to have to support this at 3am when it crashes in production.Tue, 09 Oct 2012 12:10:00 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370495.aspxThanks, I am going through your link.
But we can pass the parameter for the function.Tue, 09 Oct 2012 11:08:34 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370423.aspxYour data structure for this is going to cause you nothing but grief. How do you know what the "root" of the task is?
This is a running total type of problem but at the base is this denormalized table. You don't need a recursive function for this. Take a look at this article from Jeff Moden on running totals. [url=http://www.sqlservercentral.com/articles/T-SQL/68467/]http://www.sqlservercentral.com/articles/T-SQL/68467/[/url]Tue, 09 Oct 2012 08:33:27 GMTSean LangeRE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370415.aspxThanks for your response.
Well, I am trying to have a recursive function for the below calculation
Calculation starts fromt the last task 1.5.1.1.1
(level_task*duaration_task) + percent_task (5*6)+10 = 40
the result goes to percent_task of above task that is 1.5.1.1
in 1.5.1.1 (4*6)+40(result from the below) = 64
goes like that untill task 1.5, where 1.5 will have 94 as the value.
From 1.4 new calaculation, since it doesnt have any child task value will be 40
For task 1.3 = 20
like that for task 1.2 = 123
In the End we need to add the task 1.5+1.4.+1.3+1.2+1.1
I hope, this is more understandable.Tue, 09 Oct 2012 08:17:54 GMTsqlSer12RE: Recursive function - sql2008https://www.sqlservercentral.com/Forums/FindPost1370113.aspxI haven't been able to quite figure out what it is you want in the end, but the following code traverses your data in the proper order starting at the top.
Based on this, what is it you are trying to accomplish?
[code="sql"]
Create table dbo.TestData (
id_task int,
id_fathertask int,
level_task int,
duracion_task int,
percent_task int null,
name_task varchar(24)
);
go
insert into dbo.TestData
values
(1,1,1,76,NULL,'Task 1'),
(2,1,2,60,NULL,'Task,1.1'),
(3,2,3,2,100,'Task,1.1.1'),
(4,2,3,38,NULL,'Task,1.1.2'),
(5,4,4,10,100,'Task,1.1.2.1'),
(6,4,4,22,20,'Task,1.1.2.2'),
(7,4,4,5,35,'Task,1.1.2.3'),
(8,4,4,1,40,'Task,1.1.2.4'),
(9,2,3,20,NULL,'Task,1.1.3'),
(10,9,4,20,20,'Task,1.1.3.1'),
(11,1,2,9,NULL,'Task,1.2'),
(12,11,3,2,0,'Task,1.2.1'),
(13,11,3,7,NULL,'Task,1.2.2'),
(14,13,4,2,50,'Task,1.2.2.1'),
(15,13,4,5,50,'Task,1.2.2.2'),
(16,1,2,10,0,'Task,1.3'),
(17,1,2,20,0,'Task,1.4'),
(18,1,2,6,NULL,'Task,1.5'),
(19,18,3,6,NULL,'Task,1.5.1'),
(20,19,4,6,NULL,'Task,1.5.1.1'),
(21,20,5,6,10,'Task,1.5.1.1.1');
go
with BaseData as (
select
id_task,
id_fathertask,
level_task,
duracion_task,
percent_task,
name_task,
task_level = 1 -- for comparision purposes
from
dbo.TestData
where
id_task = id_fathertask
union all
select
td.id_task,
td.id_fathertask,
td.level_task,
td.duracion_task,
td.percent_task,
td.name_task,
task_level = bd1.task_level + 1
from
dbo.TestData td
inner join BaseData bd1
on (td.id_fathertask = bd1.id_task and td.id_task <> td.id_fathertask)
)
select * from BaseData order by name_task;
go
drop table dbo.TestData;
go
[/code]
Mon, 08 Oct 2012 17:33:55 GMTLynn Pettis