No, it's a good question.
You could look after:
select object_schema_name(ep.major_id) [Schema],
object_name(ep.major_id) TableName,
c.column_id ColumnId,
c.name ColumnName,
ep.value [Description]
from sys.extended_properties as ep
inner join sys.sysobjects as so on so.id = ep.major_id
left outer join sys.columns as c on c.object_id = ep.major_id and c.column_id = ep.minor_id
where so."type" = 'U' and so.name <> 'sysdiagrams' and ep.class_desc = 'object_or_column' and ep.name = 'MS_Description'
order by object_schema_name(ep.major_id), object_name(ep.major_id);