No problem.

Shifting gears a bit, you'll get faster and better answers in the future if you provide your data in a readily consumable format, like this....

 SELECT *
   INTO #TestTable
   FROM (VALUES 
         ('Order1', 4)
        ,('Order2',12)
        ,('Order3',12)
        ,('Order4',12)
        ,('Order5',29)
        ,('Order6',31)
        ,('Order7',49)
        )v(OrderID,Point)
;


Try this with that data.  I threw in one of the obvious extra columns that I thought you might also be looking for.

 SELECT  OrderID
        ,Point
        ,GroupCode      = DENSE_RANK()OVER (ORDER BY Point)
        ,OrdersInGroup  = COUNT(*) OVER (PARTITION BY Point)
   FROM #TestTable
  ORDER BY GroupCode, OrderID
;


Here are the results.