December 28, 2017 at 1:38 pm
Hi All,
Could anyone please advise how to go about finding table constraints down to the column level, to show which columns are involved? I'm in the process of working on a script to drop/recreate a table, but need to make sure that all constraints are restored, and to do so on the correct columns. I've already found these statements:
Select *
From INFORMATION_SCHEMA.TABLE_CONSTRAINTS
Where TABLE_NAME = 'TableName'
AND TABLE_SCHEMA = 'SchemaName'
and
select s1.name as from_schema,
o1.Name as from_table ,
s2.name as to_schema,
o2.Name as to_table
from sys.foreign_keys fk
inner join sys.objects o1 on fk.parent_object_id = o1.object_id
inner join sys.schemas s1 on o1.schema_id = s1.schema_id
inner join sys.objects o2 on fk.referenced_object_id = o2.object_id
inner join sys.schemas s2 on o2.schema_id = s2.schema_id
WHERE o1.name = 'TableName'
OR o2.name = 'TableName'
but it doesn't looke like they include column level detail.
Thanks in advance for your advice!
December 28, 2017 at 2:13 pm
Hopefully you'll get some informative answers as this is a good question!
When I've done this sort of thing, I used ssms script objects functionality, and in details I check box the stuff I want to generate create scripts for and just really really hoped I didn't miss anything. Doing it yourself could be an interesting project and it would be interesting if this thread generates a complete set of queries. My google foo isn't very good, I'm just glomming onto hopefully a good thread!
These are pretty good:
sp_help <tablename>
sp_helpconstraint <tablename>
here's a possibility for some check constraints:
select chk.definition, *
from sys.check_constraints chk
inner join sys.columns col
on chk.parent_object_id = col.object_id
inner join sys.tables st
on chk.parent_object_id = st.object_id
I got that and other info from:
https://stackoverflow.com/questions/14229277/sql-server-2008-get-table-constraints
Sorry for the junky post, I can delete it when the inevitable superior posts start piling in.
(edited for formatting)
December 28, 2017 at 3:12 pm
Not a superior post but wanted to mention that I think you need more than just columns if you want to recreate the constraints. What about the definitions for check constraints and default constraints?
Sue
December 28, 2017 at 3:35 pm
patrickmcginnis59 10839 - Thursday, December 28, 2017 2:13 PMsp_helpconstraint <tablename>
That is the most complete one out of the lists as it includes definitions but doesn't have the columns.
For the foreign key columns, sys.foreign_key_columns
For primary key and unique constraint columns, sys.indexes and sys.indexes_columns I think is what I used before. I'm just too lazy to find what I used before right now so I'll wait for that superior post as well. 🙂
All I can find now is what I use to lists all the constraints by table - no columns or definitions:
SELECT
o.[name] as ConstraintName,
OBJECT_NAME(parent_object_id) AS TableName,
schema_name(o.[schema_id]) as SchemaName,
o.type_desc as ConstraintType
FROM sys.objects AS o
WHERE o.[type] IN ('D','C','F','PK','UQ')
and OBJECT_NAME(parent_object_id) like 'Your Table Name'
ORDER BY o.[type];
Sue
December 28, 2017 at 3:46 pm
This will give you a list of the system views that have information on check, default, and other constraints >
select * from sys.all_views
where [name] like '%constraint%'
From here I would focus on the constraint name and check against it against source control.
If you dont have or cannot access source countrol.. you have to get a little creative.
As a catalyst, I like to refer to my trusty adventureWorks database.
Something akin to >
select
distinct OBJECT_NAME(parent_object_id) as tableWithConstraint
from sys.default_constraints
union
/* get from check constraints, etc... */
and put those names in a temp table.
You can then employ a cursor to to run the sp_helpconstraint command on each of those tables.
Try one case on your own
sp_helpconstraint 'sales.salesTerritory'
As I said, this is to get you started with a creative approach to the solution. You can always output the results to a text file. Play around with it and the solution unfolds.
----------------------------------------------------
December 28, 2017 at 4:03 pm
Here's how I get Foreign Key info:
SELECT
FK.name,
SCHEMA_NAME(FK.schema_id) AS schemaName,
OBJECT_NAME(FK.parent_object_id) AS parentTableName,
parentCols.name AS parentColumnName,
OBJECT_NAME(FK.referenced_object_id) AS referencedTableName,
referencedCols.name AS referencedColumnName
FROM
sys.foreign_keys AS FK
JOIN sys.foreign_key_columns AS FKCols
ON FK.parent_object_id = FKCols.parent_object_id AND
FK.object_id = FKCols.constraint_object_id AND
FK.referenced_object_id = FKCols.referenced_object_id
JOIN sys.columns AS parentCols
ON FKCols.parent_object_id = parentCols.object_id AND
FKCols.parent_column_id = parentCols.column_id
JOIN sys.columns AS referencedCols
ON FKCols.referenced_object_id = referencedCols.object_id AND
FKCols.referenced_column_id = referencedCols.column_id;
Here's how I'd get other constraints:
SELECT
DC.name AS ConstraintName,
DC.type_desc AS ConstraintType,
DC.definition AS ConstraintDefinition,
OBJECT_SCHEMA_NAME(DC.schema_id) AS SchemaName,
OBJECT_NAME(DC.parent_object_id) AS TableName,
C.name AS ColumnName
FROM
sys.default_constraints AS DC
JOIN sys.columns AS C
ON DC.parent_object_id = C.object_id AND
DC.parent_column_id = C.column_id
UNION ALL
SELECT
CC.name,
CC.type_desc,
CC.definition,
CC.schema_id,
OBJECT_SCHEMA_NAME(CC.schema_id) AS SchemaName,
OBJECT_NAME(CC.parent_object_id),
C.name AS ColumnName
FROM
sys.check_constraints AS CC
JOIN sys.columns AS C
ON CC.parent_object_id = C.object_id AND
CC.parent_column_id = C.column_id
UNION ALL
SELECT
KC.name,
KC.type_desc,
NULL AS Defintion,
OBJECT_SCHEMA_NAME(KC.schema_id) AS SchemaName,
OBJECT_NAME(KC.parent_object_id),
C.name
FROM
sys.key_constraints AS KC
JOIN sys.indexes AS I
ON KC.unique_index_id = I.index_id AND
KC.parent_object_id = I.object_id
JOIN sys.index_columns AS IC
ON I.index_id = IC.index_id AND
I.object_id = IC.object_id
JOIN sys.columns AS C
ON IC.column_id = C.column_id AND
IC.object_id = C.object_id
Jack Corbett
Consultant - Straight Path Solutions
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December 29, 2017 at 3:47 pm
I uploaded some pictures to help illustrate what was mentioned in a prior post. You can right click the database, select the tables you want to script out and what level of details through the advanced scripting options. You can save the results to a file or to a new editor window.
----------------------------------------------------
January 18, 2018 at 11:05 am
Jack Corbett - Thursday, December 28, 2017 4:03 PMHere's how I get Foreign Key info:
SELECT
FK.name,
SCHEMA_NAME(FK.schema_id) AS schemaName,
OBJECT_NAME(FK.parent_object_id) AS parentTableName,
parentCols.name AS parentColumnName,
OBJECT_NAME(FK.referenced_object_id) AS referencedTableName,
referencedCols.name AS referencedColumnName
FROM
sys.foreign_keys AS FK
JOIN sys.foreign_key_columns AS FKCols
ON FK.parent_object_id = FKCols.parent_object_id AND
FK.object_id = FKCols.constraint_object_id AND
FK.referenced_object_id = FKCols.referenced_object_id
JOIN sys.columns AS parentCols
ON FKCols.parent_object_id = parentCols.object_id AND
FKCols.parent_column_id = parentCols.column_id
JOIN sys.columns AS referencedCols
ON FKCols.referenced_object_id = referencedCols.object_id AND
FKCols.referenced_column_id = referencedCols.column_id;Here's how I'd get other constraints:
SELECT
DC.name AS ConstraintName,
DC.type_desc AS ConstraintType,
DC.definition AS ConstraintDefinition,
OBJECT_SCHEMA_NAME(DC.schema_id) AS SchemaName,
OBJECT_NAME(DC.parent_object_id) AS TableName,
C.name AS ColumnName
FROM
sys.default_constraints AS DC
JOIN sys.columns AS C
ON DC.parent_object_id = C.object_id AND
DC.parent_column_id = C.column_id
UNION ALL
SELECT
CC.name,
CC.type_desc,
CC.definition,
CC.schema_id,
OBJECT_SCHEMA_NAME(CC.schema_id) AS SchemaName,
OBJECT_NAME(CC.parent_object_id),
C.name AS ColumnName
FROM
sys.check_constraints AS CC
JOIN sys.columns AS C
ON CC.parent_object_id = C.object_id AND
CC.parent_column_id = C.column_id
UNION ALL
SELECT
KC.name,
KC.type_desc,
NULL AS Defintion,
OBJECT_SCHEMA_NAME(KC.schema_id) AS SchemaName,
OBJECT_NAME(KC.parent_object_id),
C.name
FROM
sys.key_constraints AS KC
JOIN sys.indexes AS I
ON KC.unique_index_id = I.index_id AND
KC.parent_object_id = I.object_id
JOIN sys.index_columns AS IC
ON I.index_id = IC.index_id AND
I.object_id = IC.object_id
JOIN sys.columns AS C
ON IC.column_id = C.column_id AND
IC.object_id = C.object_id
By the way, thanks Jack...this was brilliant...your 1st query returned exactly what I was looking for. 🙂
January 18, 2018 at 2:31 pm
Great glad I could help and thanks for letting me know that it helped you out.
Jack Corbett
Consultant - Straight Path Solutions
Check out these links on how to get faster and more accurate answers:
Forum Etiquette: How to post data/code on a forum to get the best help
Need an Answer? Actually, No ... You Need a Question
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