DaveDB (1/24/2014)
This comment is very insulting."Perhaps the reason for my request for additional material is becoming clearer now.
The fact that accomplished professionals, who would usually be able to answer this question while simultaneously juggling on a unicycle, are having to guess your requirements is proof enough."
All I asked was.... "How can you filter Saturday and Sunday out of a query". You do not need a result set for this particular question and if you do.... well.... then it's on you. I am not looking for trouble, but in all honesty, you seem more interested in playing gatekeeper to SSC than actually answering questions. Did you really not understand my question? MSDN Forums didn't seem to have an issue.
* shrug
Nonsense. Here's a gift for you to show that neither Phil nor anyone else who has responded on this thread means any ill will:
CREATE FUNCTION [dbo].[IF_Calendar]
(
@StartDate DATE,
@EndDate DATE,
@FirstWeekDay VARCHAR(10)
)
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
(
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a CROSS JOIN E1 b), --10E+2 or 100 rows
E3(N) AS (SELECT 1 FROM E2 a CROSS JOIN E2 b), --10E+4 or 10,000 rows max
iTally AS ( -- generate sufficient rows to cover startdate to enddate inclusive
SELECT TOP(1+DATEDIFF(DAY,@StartDate,@EndDate))
rn = ROW_NUMBER() OVER(ORDER BY (SELECT NULL))-1
FROM E3
)
-- Do some date arithmetic
SELECT
a.DateRange,
c.[Year],
c.[Month],
c.[DayOfMonth],
c.AbsWeekno,
c.[DayName],
d.Holiday
FROM iTally
CROSS APPLY (SELECT DateRange = DATEADD(day,rn,@StartDate)) a
CROSS APPLY (VALUES ('Tuesday',1),('Wednesday',2),('Thursday',3),('Friday',4),('Saturday',5),('Sunday',6),('Monday',7)
) b (FirstWeekDay, FirstWeekdayOffset)
CROSS APPLY (
SELECT
[Year] = YEAR(a.DateRange),
[Month] = MONTH(a.DateRange),
[DayOfMonth] = DAY(a.DateRange),
AbsWeekno= DATEDIFF(day,FirstWeekdayOffset,a.DateRange)/7,
[DayName]= DATENAME(weekday,a.DateRange)
) c
CROSS APPLY (
SELECT Holiday = CASE
WHEN [Month] = 1 AND [DayOfMonth] = 1 THEN 'New Year'
WHEN [Month] = 5 AND [DayOfMonth] >= 25 AND [DayName] = 'Monday' THEN 'Memorial Day'
WHEN [Month] = 7 AND [DayOfMonth] = 4 THEN 'Independence Day'
WHEN [Month] = 9 AND [DayOfMonth] <= 7 AND [DayName] = 'Monday' THEN 'Labor Day'
WHEN [Month] = 11 AND [DayOfMonth] BETWEEN 22 AND 28 AND [DayName] = 'Thursday' THEN 'Thanksgiving Day'
WHEN [Month] = 12 AND [DayOfMonth] = 25 THEN 'Christmas Day'
ELSE NULL END
) d
WHERE b.FirstWeekDay = @FirstWeekDay
)
GO
My son juggles whilst riding his unicycle. He earns cash from it, entertaining folks outside nightclubs. Nice little earner for a mech eng student.
For fast, accurate and documented assistance in answering your questions, please read this article.
Understanding and using APPLY, (I) and (II) Paul White
Hidden RBAR: Triangular Joins / The "Numbers" or "Tally" Table: What it is and how it replaces a loop Jeff Moden