Home Forums Reporting Services Reporting Services 2008 Development Division by Zero Error RE: Division by Zero Error

  • July 1, 2013 at 2:16 pm

    #1628839

    I got it to work using the following logic:

    =IIF(a > 0, 200/IIF(a = 0, 1, a), 0)

    Thanks for the help. Much appreciated.