• John Mitchell-245523 (5/16/2013)


    Sean Lange (5/16/2013)


    John Mitchell-245523 (5/16/2013)


    Phil Parkin (5/16/2013)


    lnardozi 61862 (5/16/2013)


    Just for completeness sake, you never use more than one UNION, which is the last one. All the rest should be UNION ALL.

    Why not?

    I suppose because UNION eliminates duplicates you only need to do it once - as long as you make sure that UNION is the last one evaluated. I don't know whether the query optimizer is smart enough to do that implicitly if you use more than one UNION - so it may or may not make a difference from a performance point of view.

    John

    But that is only good if you want to eliminate ALL duplicates. It is very possible that you have 3 tables and in the first 2 tables you want duplicates but if the same value shows up in the third table you want only distinct values. Other times maybe you want to include all duplicates.

    The blanket statement that "you never use more than one UNION, which is the last one. All the rest should be UNION ALL." is just completely not true. There are time when that is correct but not always.

    I'm not sure I understand. Those duplicates from the first two tables will be eliminated by the UNION operator. Try this:

    SELECT * FROM (VALUES (1), (1), (2)) x(A)

    UNION ALL

    SELECT * FROM (VALUES (2), (3), (3)) y(B)

    UNION

    SELECT * FROM (VALUES (4)) z(C)

    John

    The difference is that you don't have any values in z that are also in either of the first two tables.

    Let's say you wanted distinct values from x and y but you wanted to include duplicates from z if they exist. In this scenario you have to change the order of the UNION and UNION ALL.

    SELECT * FROM (VALUES (1), (1), (2)) x(A)

    UNION

    SELECT * FROM (VALUES (2), (3), (3)) y(B)

    UNION ALL

    SELECT * FROM (VALUES (4), (1)) z(C)

    --EDIT--

    Didn't see Eugene's post before I hit reply. I agree that you should not mix them unless it is really necessary. It does however prove that the blanket statement posted above is just not true. As with nearly everything in SQL "it depends". 😛

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