January 18, 2013 at 8:34 am
Please forgive my ignorance if this is a simple fix but I am having a brain cramp. The goal: derive new records with subtotals of a recordset.
Source recordset:
index, workcode, value
1, CL, 5
2, CL, 10
3, CL, 10
4, LI, 10
5, LI, 10
6, ME, 5
7, ME, 5
8, CL, 10
9, CL, 10
10, CL, 5
11, ME, 10
12, ME, 10
Output:
1, CL, 25
4, LI, 20
6, ME, 10
8, CL, 25
11, ME, 20
Notice that each break of the code is what triggers a new output record. Any assistance on TSQL code for accomplishing this would be greatly appreciated.
Thanks in advance!
January 18, 2013 at 8:52 am
Oops, bad code deleted!
If you haven't even tried to resolve your issue, please don't expect the hard-working volunteers here to waste their time providing links to answers which you could easily have found yourself.
January 18, 2013 at 8:56 am
Using the technique here http://www.sqlservercentral.com/articles/T-SQL/71550/
WITH SourceRecordset AS (
SELECT [index], workcode, value
FROM (
VALUES(1, 'CL', 5),
(2, 'CL', 10),
(3, 'CL', 10),
(4, 'LI', 10),
(5, 'LI', 10),
(6, 'ME', 5),
(7, 'ME', 5),
(8, 'CL', 10),
(9, 'CL', 10),
(10, 'CL', 5),
(11, 'ME', 10),
(12, 'ME', 10)
) d([index], workcode, value)
),
Grouped AS (
SELECT [index], workcode, value,
ROW_NUMBER() OVER(ORDER BY [index])-
ROW_NUMBER() OVER(PARTITION BY workcode ORDER BY [index]) AS rnDiff
FROM SourceRecordset)
SELECT MIN([index]) AS [index],
workcode,
SUM(value) AS value
FROM Grouped
GROUP BY workcode,rnDiff
ORDER BY MIN([index]);
____________________________________________________
Deja View - The strange feeling that somewhere, sometime you've optimised this query before
How to get the best help on a forum
http://www.sqlservercentral.com/articles/Best+Practices/61537January 18, 2013 at 9:07 am
Thank you for this. I will test it on my system to verify that I am getting the desired results.
January 18, 2013 at 9:13 am
Your solution worked perfectly! Thank you!
January 20, 2013 at 6:05 pm
Mark - I'm not sure why you used two window functions:
WITH SourceRecordset AS (
SELECT [index], workcode, value
FROM (
VALUES(1, 'CL', 5),
(2, 'CL', 10),
(3, 'CL', 10),
(4, 'LI', 10),
(5, 'LI', 10),
(6, 'ME', 5),
(7, 'ME', 5),
(8, 'CL', 10),
(9, 'CL', 10),
(10, 'CL', 5),
(11, 'ME', 10),
(12, 'ME', 10)
) d([index], workcode, value)
)
SELECT [index]=MIN([index]), workcode=MAX(workcode), value=SUM(value)
FROM (
SELECT [index], workcode, value
,rn=[index]-ROW_NUMBER() OVER (PARTITION BY workcode ORDER BY [index])
FROM SourceRecordset) a
GROUP BY rn
ORDER BY [index]
My thought question: Have you ever been told that your query runs too fast?
My advice:
INDEXing a poor-performing query is like putting sugar on cat food. Yeah, it probably tastes better but are you sure you want to eat it?
The path of least resistance can be a slippery slope. Take care that fixing your fixes of fixes doesn't snowball and end up costing you more than fixing the root cause would have in the first place.
Need to UNPIVOT? Why not CROSS APPLY VALUES instead?[/url]
Since random numbers are too important to be left to chance, let's generate some![/url]
Learn to understand recursive CTEs by example.[/url]
[url url=http://www.sqlservercentral.com/articles/St
January 21, 2013 at 1:46 am
dwain.c (1/20/2013)
Mark - I'm not sure why you used two window functions:
WITH SourceRecordset AS (
SELECT [index], workcode, value
FROM (
VALUES(1, 'CL', 5),
(2, 'CL', 10),
(3, 'CL', 10),
(4, 'LI', 10),
(5, 'LI', 10),
(6, 'ME', 5),
(7, 'ME', 5),
(8, 'CL', 10),
(9, 'CL', 10),
(10, 'CL', 5),
(11, 'ME', 10),
(12, 'ME', 10)
) d([index], workcode, value)
)
SELECT [index]=MIN([index]), workcode=MAX(workcode), value=SUM(value)
FROM (
SELECT [index], workcode, value
,rn=[index]-ROW_NUMBER() OVER (PARTITION BY workcode ORDER BY [index])
FROM SourceRecordset) a
GROUP BY rn
ORDER BY [index]
Sure, but that requires [index] to be contiguous- it wasn't clear from OP whether than was the case.
____________________________________________________
Deja View - The strange feeling that somewhere, sometime you've optimised this query before
How to get the best help on a forum
http://www.sqlservercentral.com/articles/Best+Practices/61537Viewing 7 posts - 1 through 6 (of 6 total)
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