Home Forums Article Discussions Article Discussions by Author Discuss content posted by Tom Thomson Variant Order 2 RE: Variant Order 2

  • January 18, 2013 at 5:09 am

    #1578647

    440692 I am just a number (12/5/2011)

    Thank you

    A very interesting question.

    Alas, I could see no other way to work out the answer, than to run the code.

    +1

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    Dineshbabu
    Desire to learn new things..