Lidou123 (11/28/2012)

---

Hi Jeff,

Thank you for your answer.

For my company, the first day of the week is Monday.

And the weeks are numbered by the start of the year.

We use the ISO Calendar.

All I want is to determine when a week is between two months, how many days are in the month M and how many are in the Month M+1.

I found the sql script in a Oracle forum but I don't know to translate it into T-SQL.

This is the URL where i found the Oracle Script. It s a french forum :)) : http://www.developpez.net/forums/d908298/bases-donnees/oracle/sql/nb-jours-semaine-cheval-2-mois/

And this the Oracle script:

WITH cal AS

(

SELECT date '2010-01-01' + level -1 AS dt

FROM dual

connect BY level <= 365

)

, sr AS

(

SELECT to_char(dt, 'yyyy-mm') AS mois ,

to_char(dt, 'iyyy"W"iw') AS iweek,

count(*) AS nb_jours,

count(*) over(partition BY to_char(dt, 'iyyy"W"iw')) AS nb_mois

FROM cal

GROUP BY to_char(dt, 'yyyy-mm'),

to_char(dt, 'iyyy"W"iw')

)

SELECT *

FROM sr

WHERE nb_mois = 2

ORDER BY mois ASC, iweek ASC;

MOIS IWEEK NB_DAY NB_MONTH

------- ------- ---------- ----------

2010-03 2010W13 3 2

2010-04 2010W13 4 2

2010-04 2010W17 5 2

2010-05 2010W17 2 2

2010-05 2010W22 1 2

2010-06 2010W22 6 2

2010-06 2010W26 3 2

2010-07 2010W26 4 2

2010-07 2010W30 6 2

2010-08 2010W30 1 2

2010-08 2010W35 2 2

2010-09 2010W35 5 2

2010-09 2010W39 4 2

2010-10 2010W39 3 2

2010-11 2010W48 2 2

2010-12 2010W48 5 2

I am waiting your answer.