Here is a query to find all the indexes on a table.

select r.[name] as table_name, i.[name] as index_name, c.[name] as column_name

FROM sys.index_columns l

inner join sys.tables r on

l.object_id = r.object_id

inner join sys.indexes i on

l.object_id = i.object_id

and l.index_id = i.index_id

inner join sys.columns c on

l.object_id = c.object_id

and l.column_id = c.column_id

where r.[name] = 'table_name_here'

order by r.[name], l.index_id, l.key_ordinal