Home Forums Article Discussions Article Discussions by Author Discuss content posted by Tom Thomson Variant order 1 RE: Variant order 1

  • November 30, 2011 at 2:31 am

    #1414503

    Answer is v1 > v2v1 > v3v3 = v2v4 > v1

    and not "v1 > v2v1 > v3v2 = v3v4 > v1"