Home Forums Article Discussions Article Discussions by Author Discuss content posted by Tom Thomson Variant order 1 RE: Variant order 1
CaptainStu72
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November 30, 2011 at 1:57 am
#1414489
Must say I agree with Henrico Bekker, the case statements at no point say v2 = v3, but rather v3 = v2. Whilst the mean the same thing, I agree that None of the Above should also be an applicable answer for those who are being pedantic.