• SQLkiwi (7/18/2011)


    CTEs generally don't help - the expression is evaluated twice.

    I included the TOP trick as the only way I know to force the query processor to evaluate just once.

    Here is another way then (learned from Stefan G) to force the calculation to only happen once:

    ;with calc(result) as

    (

    select COALESCE(@A, @b-2, @C, @D)

    union all

    select null

    from calc

    where 1=0

    )

    select calc.result * ((sign(calc.result) + 1) / 2)

    from calc

    The recursive part of the CTE returns no extra data, but coerces sql into storing the results (it will plop the results in tempdb once there are enough I believe) rather than re-evaluating them - it's a nice little trick that can sometimes help.

    MM



    select geometry::STGeomFromWKB(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

  • Forum Etiquette: How to post Reporting Services problems
  • [/url]
  • Forum Etiquette: How to post data/code on a forum to get the best help - by Jeff Moden
  • [/url]
  • How to Post Performance Problems - by Gail Shaw
  • [/url]