I have to get a count of orders placed between 1 pm yesterday and 1 pm today by day

  • The table looks like this
    OrderNo, OrderDate
    908, 1/3/2018 13:20:34
    909, 1/3/2018 15:18:41
    910, 1/4/2018 09:15:21
    911, 1/4/2018 17:09:44
    912, 1/4/2018 18:20:35
    913, 1/5/2018 22:20:35

    Expected Result

    Date, Count
    1/4/2018, 3
    1/5/2018, 2
    1/6/2018, 1

    Any help is really appreciated

    Thanks

  • QuietCoder - Monday, January 8, 2018 2:04 PM

    The table looks like this
    OrderNo, OrderDate
    908, 1/3/2018 13:20:34
    909, 1/3/2018 15:18:41
    910, 1/4/2018 09:15:21
    911, 1/4/2018 17:09:44
    912, 1/4/2018 18:20:35
    913, 1/5/2018 22:20:35

    Expected Result

    Date, Count
    1/4/2018, 3
    1/5/2018, 2
    1/6/2018, 1

    Any help is really appreciated

    Thanks

    What have you tried?

  • Here's one way:


    SELECT CAST(DATEADD(HOUR, 11, OrderDate) AS date) AS Date,
      COUNT(*) AS Count
    FROM (VALUES
     (908, '1/3/2018 13:20:34'),(
    909, '1/3/2018 15:18:41'),(
    910, '1/4/2018 09:15:21'),(
    911, '1/4/2018 17:09:44'),(
    912, '1/4/2018 18:20:35'),(
    913, '1/5/2018 22:20:35') ) x(OrderNo, OrderDate)
    GROUP BY CAST(DATEADD(HOUR, 11, OrderDate) AS date)
    ORDER BY CAST(DATEADD(HOUR, 11, OrderDate) AS date)

    SQL DBA,SQL Server MVP(07, 08, 09) A socialist is someone who will give you the shirt off *someone else's* back.


  • SELECT CAST(OrderDate AS DATE) AS [Date], COUNT(1) AS [Count]
    FROM [OrderTable]
    GROUP BY CAST(OrderDate AS DATE)
    ORDER BY COUNT(1) DESC

  • RandomStream - Monday, January 8, 2018 3:01 PM


    SELECT CAST(OrderDate AS DATE) AS [Date], SUM(1) AS [Count]
    FROM [OrderTable]
    GROUP BY CAST(OrderDate AS DATE)
    ORDER BY SUM(1) DESC

    That will sum the orders by date but the poster needs them done based on 1:00 pm previous to 1:00 pm current. So those on the 1/3/2018 would be counted towards the 1/4/2018 as they occurred after 1:00 pm. And there is one before 1:00 pm on 1/4/2018. So 1/3/2018 would be 0, 1/4/2018 would be 3, etc.

    Sue

  • Thank you Scott!

  • QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

  • Lynn Pettis - Monday, January 8, 2018 3:39 PM

    QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

    Sorry, I had only gotten up to something like Random Stream posted above

    Thanks

  • QuietCoder - Monday, January 8, 2018 3:42 PM

    Lynn Pettis - Monday, January 8, 2018 3:39 PM

    QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

    Sorry, I had only gotten up to something like Random Stream posted above

    Thanks

    I posted the request just minutes after you posted your question.

  • Lynn Pettis - Monday, January 8, 2018 4:07 PM

    QuietCoder - Monday, January 8, 2018 3:42 PM

    Lynn Pettis - Monday, January 8, 2018 3:39 PM

    QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

    Sorry, I had only gotten up to something like Random Stream posted above

    Thanks

    I posted the request just minutes after you posted your question.

    I know and I knew what I had wasn't anywhere close to the answer. I'm new here, I'll post whatever I have next time 🙂

  • QuietCoder - Monday, January 8, 2018 4:14 PM

    Lynn Pettis - Monday, January 8, 2018 4:07 PM

    QuietCoder - Monday, January 8, 2018 3:42 PM

    Lynn Pettis - Monday, January 8, 2018 3:39 PM

    QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

    Sorry, I had only gotten up to something like Random Stream posted above

    Thanks

    I posted the request just minutes after you posted your question.

    I know and I knew what I had wasn't anywhere close to the answer. I'm new here, I'll post whatever I have next time 🙂

    It still would have been nice to know what you had tried.  It is a learning thing.  I had an answer in 10 minutes, I just wanted to see what you tried before posting it.

  • Lynn Pettis - Monday, January 8, 2018 4:20 PM

    QuietCoder - Monday, January 8, 2018 4:14 PM

    Lynn Pettis - Monday, January 8, 2018 4:07 PM

    QuietCoder - Monday, January 8, 2018 3:42 PM

    Lynn Pettis - Monday, January 8, 2018 3:39 PM

    QuietCoder - Monday, January 8, 2018 3:31 PM

    Thank you Scott!

    Too bad you never posted what you had tried.

    Sorry, I had only gotten up to something like Random Stream posted above

    Thanks

    I posted the request just minutes after you posted your question.

    I know and I knew what I had wasn't anywhere close to the answer. I'm new here, I'll post whatever I have next time 🙂

    It still would have been nice to know what you had tried.  It is a learning thing.  I had an answer in 10 minutes, I just wanted to see what you tried before posting it.

    Thanks Lynn. I have something more complex coming up! Will post soon

  • Sue_H - Monday, January 8, 2018 3:14 PM

    RandomStream - Monday, January 8, 2018 3:01 PM


    SELECT CAST(OrderDate AS DATE) AS [Date], SUM(1) AS [Count]
    FROM [OrderTable]
    GROUP BY CAST(OrderDate AS DATE)
    ORDER BY SUM(1) DESC

    That will sum the orders by date but the poster needs them done based on 1:00 pm previous to 1:00 pm current. So those on the 1/3/2018 would be counted towards the 1/4/2018 as they occurred after 1:00 pm. And there is one before 1:00 pm on 1/4/2018. So 1/3/2018 would be 0, 1/4/2018 would be 3, etc.

    Sue

    You're correct, Sue. My bad.

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